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garik1379 [7]
1 year ago
11

If xy + 5ey = 5e, find the value of y'' at the point where x = 0.

Mathematics
1 answer:
notka56 [123]1 year ago
6 0

Answer:

1 (only if e is not equal to 0)

Step-by-step explanation:

xy + 5ey = 5e

0y + 5ey = 5e

y = 5e/5e

y=1

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Which expression shows the distance on the number line between 2 and −7?
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D because they are 9 ponits between them so the abs are going going to remove the negative
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2 years ago
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Alinethatincludesthepoint(6, 3)hasaslopeof 2 . what isitsequationin slope -intercept form?
Marianna [84]
Hi Kay, the point-slope form of a line is given by: y - y1 = m(x - x1). Substituting the given point, (6, -8), and the slope, -2, gives: y - (-8) = -2 * (x - 6) This becomes: y + 8 = -2x + 12
3 0
1 year ago
Which statements are true regarding the diagram? Check all that apply.
Vesnalui [34]

Answer:

2.CE is contained on the line m.

4.Ray AD is the same as ray AC.

6.Angle ECB is created from CE and CB.

Step-by-step explanation:

We are given that a diagram .

We have to find which statement are true about the given diagram.

1.CB is contained on the line n.

CB is not contained on the line n because point C and B are not lying on the line n.

Therefore, it not true.

2.CE is contained on the line m.

CE is contained on the line m because point C and E are lying on the line m.

Therefore, it is true.

3.Ray BC is the same as ray CB.

A ray  has one initial point and has no terminal point.It can extend to infinity .

Ray CB has initial point C and it extends from the point B.

But there is no BC ray.

Therefore, it is not true.

4.Ray AD is the same as ray AC.

AD is a ray but AC is also

AD and AC are same because both have initial point A and extend in the same direction.

5.Angle EAD is created from AE and DA.

It is not true because angle EAD is formed by ray AE and ray AD not ray DA.

6.Angle ECB is created from CE and CB.

It is true because angle ECB is formed by ray EC and ray BC.

5 0
2 years ago
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What is the equation of the quadratic function with a vertex at (2,-25) and an x-intercept at (7,0)?
skelet666 [1.2K]

Answer:  f(x) = (x + 3)(x – 7)

Step-by-step explanation:  Use "standard form" of the function and insert values given: vertex (2,-25) intercept point (7,0)

f(x) = a(x-h)² + k   from vertex, h is 2   y is -25   from intercept,  x is 7  f(x) is 0

to find a,  0 = a(7-2)² +(-25)   0 = a(7-2)² -25  add 25 to both sides

25 = a(5)²  25 = 25a  25/25 = a  1=a  (seems useless but verifies implied "a"coefficient is 1)

f(x) = a(x-h)² + k solve to get the quadratic form

f(x) = (x-2)² -25     (x - 2)² is x² -4x +4

f(x) = x² -4x +4 -25  simplify

f(x) = x² -4x - 21   then factor

f(x) = (x + 3)(x - 7)

8 0
1 year ago
The given equation has been solved in the table. In which step was the subtraction property of equality applied?
atroni [7]

Answer:

Option (D)

Step-by-step explanation:

Subtraction property of equality tells that whatever subtracted from one side of the equation must be subtracted from the other side.

If x + 2 = 2,

By the property of subtraction of equality,

x + 2 - 2 = 2 - 2

x = 0

But in the given question,

\frac{x}{2}-7=-7

\frac{x}{2}-7+7=-7+7

shows the addition property of equality in step (2)

Therefore, subtraction property of equality was not applied.

Option (D) will be the answer.

5 0
1 year ago
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