<span>4(a^2 + 2b) - 2b
= 4a^2 + 8b - 2b
=</span> 4a^2 + 6b
Answer:
A. $301
B. $721
Step-by-step explanation:
Let $x be the amount of money they raised.
Rowena tried to put the $1 bills into two equal piles and found one left over at the end, then

Polly tried to put the $1 bills into three equal piles and found one left over at the end, then

Frustrated, they tried 4, 5, and 6 equal piles and each time had $1 left over, then

Finally Rowena put all the bills evenly into 7 equal piles, and none were left over, then

This means
is divisible by 2, 3, 4, 5 and 6 without remainder, so

Hence,

The smallest amount of money they could have raised is $301, because
is divisible by 7.
Now, the number
should be divisible by 7 and must be greater than 500.
So,

When n = 9,
is not divisible by 7.
When n = 10,
is not divisible by 7.
When n = 11,
is not divisible by 7.
When n = 12,
is divisible by 7.
B. The least amount of money they could have raised is $721
Answer:
G = 14 - 1.75(t)
Where G is the number of gallons of gas remaining;
14 represents the amount of gas in gallons in the full gas tank of the vehicle
t is the number of hours
Step-by-step explanation:
Here, we want to write an equation.
We are told that the car uses 1.75 gallons of gas every hour and after 4 hours 7 gallons were left
In the 4 hours, the amount of fuel used will be 1.75 * 4 = 7 gallons
So therefore since we have 7 gallons left, the amount of gallons in the full tank of the vehicle will be 7 + 7 = 14 gallons
Hence, the equation we want to write will be;
G = 14 - 1.75(t)
Answer:
$0
Step-by-step explanation:
A part-time landscaper made $8996.32 last year.
She claimed herself as an exemption for $3650 and had a $5700 standard deduction
Exemption means not subject to taxation.
Deduction means taking some amount of your income for the year, and not have to pay taxes on it.
So, 

Since Her income is lower than the exemption and the standard deduction.
So, her taxable income last year was $0.
Thus Option D is correct.
For this case we have the following equation:

Where,
w: The weight of a spring in pounds
E: the energy stored by the spring in joules.
Substituting values we have:

Making the corresponding calculation:
Answer:
the approximate weight of the spring in pounds is: