Answer:
(87)₁₀ = (1010111)₂
Take any base 10 number. Divide it by 2
Step-by-step explanation:
On't want to be ripped off do you?/ That's why you want to have some interest. Just in a simple form this is a rush job right now.
Answer:
0.94
Step-by-step explanation:
The question after this basically is:
<em>"If the applicant passes the "aptitude test for managers", what is the probability that the applicant will succeed in the management position?"</em>
<em />
So,
P(successful if hired) = 60% = 0.6 [let it be P(x)]
P(success at passing the test) = 85% = 0.85 [let it be P(y)]
P(successful and pass the test) = P(x) + P(y) -[P(x)*P(y)]
So,
P(successful and pass the test) = 0.6 + 0.85 - (0.6*0.85) = 0.94 (94%)
Answer:
the principal drove 384 miles
Step-by-step explanation:
12x32=384 miles
Answer:
a: 28 < µ < 34
Step-by-step explanation:
We need the mean, var, and standard deviation for the data set. See first attached photo for calculations for these...
We get a mean of 222/7 = 31.7143
and a sample standard deviation of: 4.3079
We can now construct our confidence interval. See the second attached photo for the construction steps.
They want a 90% confidence interval. Our sample size is 7, so since n < 30, we will use a t-score. Look up the value under the 10% area in 2 tails column, and degree of freedom is 6 (degree of freedom is always 1 less than sample size for confidence intervals when n < 30)
The t-value is: 1.943
We rounded down to the nearest person in the interval because we don't want to over estimate. It said 28.55, so more than 28 but not quite 29, so if we use 29 as the lower limit, we could over estimate. It's better to use 28 and underestimate a little when considering customer flow.