What is the lateral area of a cylinder which has an element of 8 inches and a right section with a perimeter of 24 inches?

Show that the three points whose position vectors are 7j+ 10k,-i + 6j+6k and - 4i + +9j + 6k form an isosceles right

Novay_Z [31]

Answer:

AB = √18 , BC=√18 and CA =4

AB²+BC² = CA² and AB=BC

ΔABC isosceles right angled triangle.

Step-by-step explanation:

Given vectors are 7j+ 10k,-i + 6j+6k and - 4i + +9j + 6k

A( 0,7,10), B( -1,6,6) C(-4,9,6)

AB⁻ = OB-OA = -I+6j+6k-(7j+10k) = -I-j-4k

AB = $\sqrt{1+1+16} = \sqrt{18}$

BC = OC-OB = -4i+9j+6k-(-I+6j+6k) = -3i+3j

BC= $\sqrt{9+9} =\sqrt{18}$

CA = OA-OC = 7j+10k - (- 4i + +9j + 6k ) = 4i-2j+4k

CA = $\sqrt{16+4+16} =\sqrt{36} =4$

Since AB²+BC² = CA²

And AB=BC

Therefore it follows that ΔABC is a right angled isosceles triangle

3 0

2 years ago

A rectangular patio has area of 180 square feet. The width of the patio is 3 feet less than the length. Find the length and widt

kondaur [170]

My calculations got to a decimal so it’s about.

6 0

2 years ago

Read 2 more answers

Angelique had 20 tokens to use for games at the arcade. She lost some of them. Her dad tripled the tokens she had left. Angeliqu

alexandr402 [8]

Answer: Both the expressions are exactly same . Both are representing the number of tokens she has now.

Step-by-step explanation:

Given: The total number of tokens Angelique has= 20

Since, she lost some of them, let the number of lost tokens be t.

Then, The remaining tokens she has = 20-t

Then her father triples the tokens she has.

now, the number of token she has= $3(20-t)$ ....>Angelique's expression

By using distributive property,

The number of token she has= $3\times20-3t$

⇒The number of token she has= $60-3t$ ...> Dante's expressions

Hence, both are the same expressions. Both are representing the number of tokens she has now.

7 0

2 years ago

Read 2 more answers

Clay can run one lap around the track in 1/4 of an hour. How many hours will it take him to run 5 1/3 laps around the track?

Jet001 [13]

Answer: It will take him 1 hour and 35 min

8 0

2 years ago

The indicated function y1(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section

LUCKY_DIMON [66]

Answer:

y2 = C1xe^(4x)

Step-by-step explanation:

Given that y1 = e^(4x) is a solution to the differential equation

y'' - 8y' + 16y = 0

We want to find the second solution y2 of the equation using the method of reduction of order.

Let

y2 = uy1

Because y2 is a solution to the differential equation, it satisfies

y2'' - 8y2' + 16y2 = 0

y2 = ue^(4x)

y2' = u'e^(4x) + 4ue^(4x)

y2'' = u''e^(4x) + 4u'e^(4x) + 4u'e^(4x) + 16ue^(4x)

= u''e^(4x) + 8u'e^(4x) + 16ue^(4x)

Using these,

y2'' - 8y2' + 16y2 =

[u''e^(4x) + 8u'e^(4x) + 16ue^(4x)] - 8[u'e^(4x) + 4ue^(4x)] + 16ue^(4x) = 0

u''e^(4x) = 0

Let w = u', then w' = u''

w'e^(4x) = 0

w' = 0

Integrating this, we have

w = C1

But w = u'

u' = C1

Integrating again, we have

u = C1x

But y2 = ue^(4x)

y2 = C1xe^(4x)

And this is the second solution

5 0

2 years ago