2 years ago

Which graph represents an exponential function?

Mathematics

1 answer:

Andreyy892 years ago

5 0

Answer:

The 1st Picture

Step-by-step explanation:

An exponential function is a base with an exponent of x. The parent graph f(x) will always have an asymptote at x= 0 and curve steeply.

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A rectangular swimming pool measures 14 feet by 30 feet. The pool is surrounded on all four sides by a path that is 3 feet wide.

V125BC [204]

Check the picture below.

since the rectangular pool is a 14x30, the top and bottom part of that rectangle in the picture are just a 3x30 piece and the sides are 3x8, so how many ft² is that?

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The price per night for a hotel room is different at three different hotels.

Damm [24]

I think you meant it to be not repeating 3 times so
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2 years ago

Washington is 44 miles south of Lawrence. and midland is 63 miles east of Lawrence. how far apart are Washington and midland?

gregori [183]

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2 years ago

If f(1) = 0 what are all the roots of the function f(x)=x^3+3x^2-x-3 use the remainder theorem.

ArbitrLikvidat [17]

Solution:

As we are given that f(1) = 0 .

It mean that $(x-1)$ is one of the factor of the given equation.

Remainder theorem can be applied as below:

$\frac{(x^3+3x^2-x-3)}{(x-1)}=\frac{x^3-x^2+4x^2-4x+3x-3}{(x-1)}\\ \\\frac{x^3-x^2+4x^2-4x+3x-3}{(x-1)}=\frac{x^2(x-1)+4x(x-1)+3(x-1)}{(x-1)} \\\\\frac{x^2(x-1)+4x(x-1)+3(x-1)}{(x-1)}=\frac{(x^2+4x+3)(x-1)}{(x-1)} \\\\\frac{(x^2+4x+3)(x-1)}{(x-1)} =\frac{(x^2+3x+x+3)(x-1)}{(x-1)} \\\\\frac{(x^2+3x+x+3)(x-1)}{(x-1)} =\frac{(x-1)(x+3)(x+1)}{(x-1)}$

Hence the factors are (x-1),(x+3) and (x+1).

Hence the correct option is B.

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