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german
1 year ago
5

Explain the error in the work shown. Find the

Mathematics
2 answers:
weeeeeb [17]1 year ago
3 0

Answer:

a = - \frac{3}{4}

Step-by-step explanation:

The correct solution of the given equation is as follows :

We have,

\frac{1}{64} = 16^{2a}

⇒ 4^{- 3} = (2^{4} )^{2a}

⇒ 2^{(2 \times (-3))} = 2^{8a}

⇒ 2^{- 6} = 2^{8a}

Comparing the power of equal base, we get

- 6 = 8a

⇒ a = - \frac{6}{8}

⇒ a = - \frac{3}{4}

Therefore, before equating the powers of two terms the base of the terms should be equal and here this is the error. (Answer)

pentagon [3]1 year ago
3 0

Answer:

The bases were not the same when the exponents were set equal to each other.

16 should have been written as 4 squared.

The exponent on the right should be 4a instead of 8a.

The correct solution is a=-3/4

Step-by-step explanation:

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Answer:

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(b) Probability that a standard normal random variable will be between .3 and 3.2 = 0.3814

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with;

    Mean, \mu = 30.05 inches        and    Standard deviation, \sigma = 0.2 inches

Let X = A sheet selected at random from the population

Here, the standard normal formula is ;

                  Z = \frac{X - \mu}{\sigma} ~ N(0,1)

(a) <em>The Probability that a sheet selected at random from the population is between 30.25 and 30.65 inches long = P(30.25 < X < 30.65) </em>

P(30.25 < X < 30.65) = P(X < 30.65) - P(X <= 30.25)

P(X < 30.65) = P(\frac{X - \mu}{\sigma} < \frac{30.65 - 30.05}{0.2} ) = P(Z < 3) = 1 - P(Z >= 3) = 1 - 0.001425

                                                                                                = 0.9985

P(X <= 30.25) = P( \frac{X - \mu}{\sigma} <= \frac{30.25 - 30.05}{0.2} ) = P(Z <= 1) = 0.84134

Therefore, P(30.25 < X < 30.65) = 0.9985 - 0.84134 = 0.15716 .

(b)<em> Let Y = Standard Normal Variable is given by N(0,1) </em>

<em> Which means mean of Y = 0 and standard deviation of Y = 1</em>

So, Probability that a standard normal random variable will be between 0.3 and 3.2 = P(0.3 < Y < 3.2) = P(Y < 3.2) - P(Y <= 0.3)

 P(Y < 3.2) = P(\frac{Y - \mu}{\sigma} < \frac{3.2 - 0}{1} ) = P(Z < 3.2) = 1 - P(Z >= 3.2) = 1 - 0.000688

                                                                                           = 0.99931

 P(Y <= 0.3) = P(\frac{Y - \mu}{\sigma} <= \frac{0.3 - 0}{1} ) = P(Z <= 0.3) = 0.61791

Therefore, P(0.3 < Y < 3.2) = 0.99931 - 0.61791 = 0.3814 .

 

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