If f (x) = StartFraction x minus 3 Over x EndFraction and g(x) = 5x – 4, what is the domain of (f circle g) (x)?
2 answers:
Answer:
<h2>The domain is all real values of x exceptStep-by-step explanation:
The function, .
g(x) = 5x - 4.
Hence, (f circle g) (x) = .
We need to find the domain of (f circle g) (x) .
The domain means the set of values of x, for which we will get a real value of (f circle g) (x).
The function will not give a real value when, 5x - 4 = 0 that is .
Hence, the domain of the function will be all real values of x rather than .
You might be interested in
Answer:
Step-by-step explanation:
step 1
Find the value of x
we know that
r is the midpoint of qs
so
QR=RS
QS=QR+RS------> QS=2RS -----> equation A
RT=RS+ST ----> equation B
see the attached figure to better understand the problem
Substitute the given values in the equation B and solve for x
step 2
Find the value of RS
substitute the value of x
step 3
Find the value of QS
Remember equation A
QS=2RS
so
Answer: $65.10
Step-by-step work:
1.Set the ratio
2.Cross-multiply
3.Divide to single out x
Step-by-step work:
1.Set the ratio
2.Cross-multiply
3.Divide to single out x
Given:
Product A requires 7 board feet of wood and 4 lbs of wicker.
Product B requires 5 board feet of wood and 5 lbs of wicker.
Product C requires 4 board feet of wood and 3 lbs of wicker.
Available wood = 3000 board feet
Available wicker = 1400 lbs
Profit margin of A = $35 per unit
Profit margin of B = $42 per unit
Profit margin of C = $20 per unit
To find:
The linear programming problem for given situation.
Solution:
Let the number of units produced of products A, B and C are x, y and z respectively.
Product A Product B Product C Total
Board feet of wood 7 5 4 3000
wicker 4 5 3 1400
Objective function: Maximize
s.t.,
Board feet of wood :
Wicker :
Number of units cannot be negative. So, .
Therefore, the required LPP is
Maximize
s.t.,