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1 year ago

The perimeter of the school crossing sign is 102 inches what is the length of each side

1 answer:

6 0

The perimeter of the school crossing sign is 102 inches
length of each side = ?
in the question number of sides is not mentioned, so the answer may vary for the length of each side. if there is 5 sides divide 102 by 5, we get 20.4 answer so in case of 5 sides length of each side is 20.4 inches. if there is 4 sides divide 102 by 4 and we get 25.5 inches answer for the legnth each side.

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The sum of Orion and Sagan’s age is 24, and the difference between their ages is 6. Find their ages given that Orion is older th

Katarina [22]

Let's say that Sagan's age is x and Orion is x + 6 (since Sagan is younger by 6 years).

We know that Orion's age + Sagan's age is 24, so x + x + 6 is 24

2x = 18

x = 9

That means that Sagan is 9, and Orion is 9+6 or 15.

6 0

1 year ago

what is the value of the constant in the equation that relates the height and width of this rectangle

Doss [256]

The correct answer is C. 1.5

You can find this answer by using any of the points on the graph and putting them into the given equation. Then you can solve for the constant. For the purpose of this example, we will use (10, 15)

Height = Constant * Width ---> Plug in known values.

15 = Constant * 10 ----> Divide both sides by 10

1.5 = Constant

This will work with whatever numbers you use from the graph. Although this graph does not have any others to really choose from.

8 0

1 year ago

Of the 2000 students attending, every 5th student going into the basketball game is asked if the school should spend more money

MA_775_DIABLO [31]

The students would show no regard for the money being spent because it is not their money

8 0

2 years ago

A recent study found that 51 children who watched a commercial for Walker Crisps (potato chips) featuring a long-standing sports

hichkok12 [17]

Answer:

The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population

$t = 3.054$

The p-value is $p-value = P(Z > 3.054) = 0.0011291$

The conclusion is

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The test statistics is

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 51$

The first sample mean is $\mu_1 = 36$

The second sample size is $n_2 = 41$

The second sample size is $\mu_2 = 25$

The first standard deviation is $\sigma _1 = 21.4 \ g$

The second standard deviation is $\sigma _2 = 12.8 \ g$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o : \mu_1 = \mu_ 2$

The alternative hypothesis is $H_a : \mu_1 > \mu_2$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \= x_2}{ \sqrt{ \frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} } }$

=> $t = \frac{ 36 - 25}{ \sqrt{ \frac{ 21.4^2}{51} + \frac{ 12.8^2}{41} } }$

=> $t = 3.054$

The p-value is mathematically represented as

$p-value = P(Z > 3.054)$

Generally from the z table

$P(Z > 3.054) = 0.0011291$

=> $p-value = P(Z > 3.054) = 0.0011291$

From the values obtained we see that $p-value < \alpha$ so the null hypothesis is rejected

Thus the conclusion is

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

5 0

2 years ago

three positive numbers are in Arithmetic Progression (A.P). the sum of the squares of the three numbers is 155. while the sum of

Alecsey [184]

Given:
Three numbers in an AP, all positive.
Sum is 21.
Sum of squares is 155.
Common difference is positive.

We do not know what x and y stand for. Will just solve for the three numbers in the AP.
Let m=middle number, then since sum=21, m=21/3=7
Let d=common difference.
Sum of squares
(7-d)^2+7^2+(7+d)^2=155
Expand left-hand side
3*7^2-2d^2=155
d^2=(155-147)/2=4
d=+2 or -2
=+2 (common difference is positive)

Therefore the three numbers of the AP are
{7-2,7,7+2}, or
{5,7,9}

6 0

2 years ago