To solve this problem, we can set up an equation, letting the unknown value of last month's supply sales be represented by the variable x.
First, we must convert 78% to its decimal equivalent, by dividing 78/100. This is because percentages are parts of a whole 100 percent.
78/100 = 0.78
Now, we are ready to set up our equation, using our knowledge that the word "of" refers to multiplication in mathematics.
3,285 = 0.78x
To solve our equation, we must divide both sides of the equation by 0.78 to get the variable x alone on the right side of the equation.
x = 4211.53846154
This means that last month's supply sales were about $4,211.54 (we round the last digit up because 8 is greater than 5).
Hope this helps!
Answer
14/15 kg
Step-by-step explanation:
Rewriting our equation with parts separated
=1+215−15
Solving the fraction parts
2/15−15=?
Find the LCD of 2/15 and 1/5 and rewrite to solve with the equivalent fractions.
LCD = 15
2/15−3/15=−1/15
Combining the whole and fraction parts
1−1/15=14/15
Solution by Formulas
converting mixed numbers to fractions, our initial equation becomes,
17/15−15
Applying the fractions formula for subtraction,
=(17×5)−(1×15)15×5
=85−15/75
=70/75
Simplifying 70/75, the answer is
=14/15
Answer:
Out of every 5 trials, the desired outcome will occur approximately 2 times
Step-by-step explanation:
The first statements states that it will happen exactly two times, but probability never guarantee the outcome
The third and fourth statement states out of 7 which cannot be true as 2-5 basically means out of 5
Maria : 26.50 - 0.25(26.50) = 26.50 - 6.625 = 19.88
19.87 + 0.10(19.87) = 19.87 + 1.99 = 21.86
Edwin : 0.75(26.50) = 19.88
1.10(19.88) = 21.86
and if they each have $ 23, then yes, they both ave enough money to buy the book. They both were correct in their calculations. Because taking 25% off, is the same as paying 75%.....and taking the discount price and subtracting 10% from that, is the same as multiplying by 110%. So they basically worked the same problem, just in a little different way...and they both ended up with the same answer
Answer:
Step-by-step explanation:
<u>1.SEPARATE THE VARIABLES AS X & Y IN NUMERATOR</u>
NOW,we can changes in the numerator variable ADDING THE POWERS THEN THE VARIABLES