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Monica [59]
2 years ago
8

What is the finance charge on $13,300 financed at 7.9 percent for 4 years if the monthly payment per $100 is $2.44?

Mathematics
1 answer:
luda_lava [24]2 years ago
5 0

If you borrowed $100, then your monthly payment is $2.44

If you borrowed $200, then your monthly payment is 2*2.44 = 4.88

etc etc

We can set up a proportion

2.44/100 = x/13300

to figure out the monthly payment x. Cross multiply and solve for x

2.44*13300 = 100*x

100x = 2.44*13300

100x = 32452

x = 32452/100

x = 324.52

So the monthly payment is $324.52

An alternative way to get this monthly payment is to apply 2.44% to 13300, which is another way to view the phrase  "monthly payment per $100 is 2.44"

------------------

There are 48 months in 4 years (start with 12 mon = 1 yr, then multiply both sides by 4) so we multiply 48 by the monthly payment to get the result 48*324.52 = 15,576.96. This is the total amount you have to pay back which is the principal plus interest.

Subtract off the principal (amount borrowed) to find the interest or finance charge: 15,576.96 - 13,300 = 2,276.96

Answer: Choice B

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A bird sanctuary needs at least 500 lbs of corn per month. The storage shed
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Answer:

x≥(500-87)/40

Step-by-step explanation:

You need 500 lbs and already have 87 so you need at least 413 bags. You divide you 40 because they come in 40 pound bags. Round up so that you have the minimum number of bags necessary to reach 500 lbs of corn.

8 0
2 years ago
A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on
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Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

Z_{1-\alpha /2}= Z_{0.95}= 1.645

[10.41±1.645*(\frac{3.71}{\sqrt{28} } )]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0
2 years ago
Kate bought a bus pass that had an initial value of
gtnhenbr [62]

The cost of one bus ride is 2% of the initial value of pass.

Step-by-step explanation:

Initial value of pass = $90

Cost of one ride = $1.80

Cost percent of one ride = \frac{Cost\ of\ one\ ride}{Initial\ value\ of\ pas}*100\\

Cost\ percent\ of\ one\ ride=\frac{1.80}{90}*100\\\\Cost\ percent\ of\ one\ ride=\frac{180}{90}\\\\Cost\ percent\ of\ one\ ride=2\%

The cost of one bus ride is 2% of the initial value of pass.

Keywords: percentage, division

Learn more about division at:

  • brainly.com/question/2821386
  • brainly.com/question/2860697

#LearnwithBrainly

8 0
2 years ago
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