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liq [111]
2 years ago
9

The vertex of a parabola that opens downward is at (0, 4). The vertex of a second parabola is at (0, –4). If the parabolas inter

sect at two points, which statement must be true?
The second parabola opens downward.
The second parabola opens upward.
The points of intersection are on the x-axis.
The points of intersection are of equal distance from the y-axis.
Mathematics
2 answers:
Karo-lina-s [1.5K]2 years ago
5 0

Answer:

b

Step-by-step explanation:

tamaranim1 [39]2 years ago
3 0

Answer:the answer is b

Step-by-step explanation:

i just finished the quiz

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Consider the first five steps of the derivation of The Quadratic function
Burka [1]

Answer:

Step-by-step explanation:

  • pick like terms

x² +  b²/4a² = -c / a + b²/4a²

  • b²/4a² = (b/2a)²

x² + (b/2a)² = -c/a + (b/2a)²

(x + b/2a)² = -c/a + (b/2a)² =  -c / a + b²/4a² = (-4ac+ b²)/4a²

(x + b/2a)² =  (-4ac+ b²)/4a²

  • square root both sides

√{(x + b/2a)²} = √{(-4ac+ b²)/4a²}

x + b/2a = √(-4ac+ b²) / √(4a²) = √(-4ac+ b²) / 2a = √( b²-4ac) / 2a

x + b/2a  =  √( b²-4ac) / 2a

  • subtract b/2a from both sides

x + b/2a -b/2a  =  {√( b²-4ac) / 2a } -b/2a

x = -b/2a +   {√( b²-4ac) / 2a }

  • the l.c.m is the same

x = {-b±√( b²-4ac)}/2a

7 0
2 years ago
last night, julie's pet hamster zoe kept julie awake for at least an hour running on her exercise wheel and scratching at the co
borishaifa [10]

Answer: x+y\geq 1, x>\frac{1}{4} ,  x\geq 2y and y\geq 0

Step-by-step explanation:

Here,  x represents the number of hours Zoe spent running on her wheel and y represents the number of hours spent scratching her cage.

Julie was awoke for at least an hour running on her exercise wheel and scratching the of her cage.

⇒ x+y\geq 1

She ran on her wheel at least twice as long as she scratched at the corners of her cage.

⇒ x\geq 2y

Also, She spent more than 1/4 hour running on her wheel.

⇒ x>\frac{1}{4}

And, we know that number of hours can not be negative.

⇒  y\geq 0

Therefore, the complete system of inequality which shows the given situation is,

x+y\geq 1, x>\frac{1}{4} and x\geq 2y, y\geq 0

Note: the feasible region ( covered by the given system) is shown in the below graph.


6 0
2 years ago
Rational number 3 by 40 is equals to​
kkurt [141]

Answer:

6/80, 9/120, 12/160 etc

8 0
2 years ago
Read 2 more answers
You are graphing rectangle ABCDABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the rectangle:
vampirchik [111]

Answer:

The given coordinates of the vertices of rectangle ABCD are A(−2,2),B(4,2),C(4,−2).

We are to plot D on the graph.

Since ABCD is a rectangle, the abscissa of D will be that of A and the ordinate of D will be that of C.

Step-by-step explanation:

3 0
1 year ago
Choose the function whose graph is given by:
loris [4]
<h2>Answer:</h2>

y=3sec\left(\frac{1}{2}x\right)

<h2>Step-by-step explanation:</h2>

The graphs of sec(x) can be obtained from  the graph of the cosine function using the reciprocal identity, so:

sec(x)=\frac{1}{cos(x)}

But in this problem, the graph stands for the function:

y=3sec\left(\frac{1}{2}x\right)

Because the period is now 4π as indicated and for x=0 in the figure and this can be proven as follows:

Period=\frac{2\pi}{\frac{1}{2}}=4\pi

Also, for \ x=1 \ then \ y=3 as indicated in the figure and this can be proven as:

y=3sec\left(\frac{1}{2}x\right) \\ \\ y=\frac{3}{cos(0.5x)} \\ \\ y=\frac{3}{cos(0.5(0))} \\ \\ y=\frac{3}{1}=3

5 0
2 years ago
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