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Ivenika [448]
1 year ago
6

To convert degrees Fahrenheit (F) into degrees Celsius (C) use the formula 2003-05-04-00-00_files/i0150000.jpg. Rewrite the equa

tion to convert degrees Celsius to degrees Fahrenheit.
A.
2003-05-04-00-00_files/i0150001.jpg
B.
2003-05-04-00-00_files/i0150002.jpg
C.
2003-05-04-00-00_files/i0150003.jpg
D.
2003-05-04-00-00_files/i0150004.jpg
Mathematics
1 answer:
mihalych1998 [28]1 year ago
6 0
To covert degrees Fahrenheit (F) to degrees Celsius (C) we use the equation C<span> = (</span>F<span> - 32) × 5/9</span> . To convert degrees Celsius (C) to degrees <span>Fahrenheit (F) we have to rewrite the equation. 
First step: Divide both sides by 5/9. The equation would look like this: 
</span>C(9/5) = (F - 32) 

Second step: Add 32 on both sides. 
32 + (9/5)C = F or F = <span>32 + (9/5)C</span>
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The cost for a different taxi company is expressed with the equation y = 1.65x + 2.35, where x represents the miles driven and y
Rudiy27
To solve this, all you have to do is plug in the 14 where the x value is:
y=1.65(14) +2.35 which equals 25.45
9 0
2 years ago
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A rectangular portrait measures 50cm by 70cm. It is surrounded by a rectangular frame of uniform width. If the area of the frame
snow_tiger [21]

Let us assume uniform width = x cm wide.

Length of rectangular portrait = 50cm and width of rectangular portrait = 70cm.

Therefore,  length of rectangle made by frame = 50 + x+x = (2x+50) cm.

And width of rectangle made by frame = 70+x+x = (2x+70) cm.

We know, the area of rectangular portrait = 50 × 70 = 3500 cm^2.

Total area of the rectangle made by frame would be =  (2x+50) * (2x+70)

We know,

Actual area of frame = Area of rectangle made by frame -  area of rectangular portrait.

We also given "the area of the frame is the same as the area of the portrait."

We can setup an equation now,

 3500 = (2x+50) * (2x+70) - 3500.

Subtracting 3500 from both sides, we get

3500-3500 = (2x+50) * (2x+70) - 3500-3500.

0 = (2x+50) * (2x+70) -7000.

FOIL (2x+50) * (2x+70), we get

0 = 2x*2x +2x*70 + 50*2x +50*70 - 7000.

0 = 4x^2 +140x +100x +3500 -7000.

4x^2 +240x -3500 = 0.

Dividing whole equation by 4, we get

x^2 +60x - 875 =0

Applying quadratic formula =\frac{-b\pm \sqrt{b^2-4ac}}{2a}, we get

=\frac{-60\pm \sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}

x=\frac{-60+\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}=5\left(\sqrt{71}-6\right)

x=\frac{-60-\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}:\quad -5\left(6+\sqrt{71}\right)

We cant take negative value.

So, x=5\left(\sqrt{71}-6\right)=12.13

We could take approximately 12 cm.



7 0
2 years ago
If the greatest integer function is called the floor function because it rounds any number down to the nearest integer, what wou
Phantasy [73]
Ceiling Function is the least integer that is greater than or equal to x.
5 0
1 year ago
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What number would you multiply the second equation by in order to eliminate the x-terms when adding to the first equation? What
alexandr402 [8]

Answer:

1. Multiply (2) by 2 to eliminate the x-terms when adding

2. Multiply (2) by 3 to eliminate the y- term

Step-by-step explanation:

Use this system of equations to answer the questions that follow.

4x-9y = 7

-2x+ 3y= 4

what number would you multiply the second equation by in order to eliminate the x-terms when adding the first equation?

4x-9y = 7 (1)

-2x+ 3y= 4 (2)

Multiply (2) by 2 to eliminate the x-terms when adding the first equation

4x-9y = 7

-4x +6y = 8

Adding the equations

4x + (-4x) -9y + 6y = 7 + 8

4x - 4x - 3y = 15

-3y = 15

y = 15/-3

= -5

what number would you multiply the second equation by in order to eliminate the y- term when adding the second equation?

4x-9y = 7 (1)

-2x+ 3y= 4 (2)

Multiply (2) by 3 to eliminate the y- term

4x - 9y = 7

-6x + 9y = 12

Adding the equations

4x + (-6x) -9y + 9y = 7 + 12

4x - 6x = 19

-2x = 19

x = 19/-2

= -9.5

x = -9.5

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1 year ago
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Ramona's backyard is fenced and represented by parallelogram YARD with measures in meters. She installed a 12-meters fence to se
Alisiya [41]
The fencing line x is the height of a rectangle triangle of base = y, hypothenuse of 9 m, so we use Pythagoras theorem to solve:

hyp^2 = height^2 + base^2
9^2 = x^2 + y^2
x^2 = 81 - y^2


we can see that x is also the height of another rectangle triangle of base = 15 - y, hypothenuse of 12 m, so we use Pythagoras theorem to solve:
hyp^2 = height^2 + base^2
12^2 = x^2 + (15 - y)^2

lets expand:
144 = x^2 + 225 - 30y + y^2

substitute x^2 from the first equation in the last:
144 = 81 - y^2 + 225 - 30y + y^2
144 = 81 + 225 - 30y
30y = -144 + 81 + 225
y = 5.4 m

substitute in the fence equation:
x^2 = 81 - y^2
x^2 = 81 - 5.4^2
x = 7.2 m that is the length of the fence



3 0
1 year ago
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