Answer:
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
A = 84 mg
Answer:
Hey there!
We can't compare two measurements without converting them to the same units. Thus, we use proportions to make all the values into the same unit.
, which converts to centimetres to millimetres.
12.5 cm=125 mm.
Now, we can compare the values of 125 mm and 140 mm.
Clearly, we see that 140 mm is greater than 125 mm.
Let me know if this helps :)
Answer:
1701 high
2712 wide
789 long
= 4413
Step-by-step explanation:
Answer:
P(working product) = .99*.99*.96*.96 = .0.903
Step-by-step explanation:
For the product to work, all four probabilities must come to pass, so that
P(Part-1)*P(Part-2)*P(Part-3)*P(Part-4)
where
P(Part-1) = 0.96
P(Part-2) = 0.96
P(Part-3) = 0.99
P(Part-4) = 0.99
As all parts are independent, so the formula is P(A∩B) = P(A)*P(B)
P (Working Product) = P(Part-1)*P(Part-2)*P(Part-3)*P(Part-4)
P (Working Product) = 0.96*0.96*0.96*0.99*0.99
P(Working Product) = 0.903
Answer:
Your answer should be AC=2DF=34
Step-by-step explanation:
