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Advocard [28]
2 years ago
12

Use area model to explain the product 4.6 and 3. Write the product in standard form, word form and expanded form.

Mathematics
2 answers:
kenny6666 [7]2 years ago
4 0
Use area model to explain the product and 4.6 3. Write the product in standard form, word form and expanded form. 
 Standard form: 4.6     3 
 Word form: 4.0 + 0.6    3
<span>expanded form: four point six      three</span>
enyata [817]2 years ago
3 0

Answer: Product = 13.8

Step-by-step explanation:

<u>As we have to use area model :</u>

So, we

Let length of rectangle be 4.6

Let breadth of rectangle be 3

As we know that

Area of rectangle is given by

Length \times breadth\\\\=4.6\times 3\\\\=13.8\text{ squared units }

Now, we must write in standard form, word form and expanded form:

So,

Standard form = 13.8

Word form = thirteen and 8 tenths

Expanded form is given by

13.8=1\times 10+3\times 1+8\times \frac{1}{10}

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A game has 3 possible outcomes: The first outcome has the probability of 1/6. The result is winning $12. The second outcome has
lapo4ka [179]
In the long run, you will lose $1 per game.

To find the expected value of this game, we have to multiply the chances by each prize. Then, add up all the possibilities.

(1/6) x $12 + (1/3) x $3 + (1/2) x $8 

2 + 1 - 4 = -1

On average, you will lose $1 per game.
7 0
2 years ago
Which is the graph of the linear inequality y &lt; 3x + 1? On a coordinate plane, a solid straight line has a positive slope and
stepan [7]

For this case we have the following inequality: y < 3x + 1 < br/ >

What we must do is to evaluate a point of the Cartesian plane and verify if it is in the shaded region.

The shaded region represents the solution of the system of equations.

For the point (0, 0) we have:

0 < 3(0) + 1 < br / >

0 < 0 + 1 < br / >

0 < 1 < br / >

Therefore, the point (0, 0) is in the shaded region because it satisfies the inequality.

Then, the points that are on the line, are not part of the solution because the sign is of less strict.

Hope I helped ~~Laurel

6 0
1 year ago
Read 2 more answers
Three cats and three dogs, A, B, C, D, E, and F, live on a street in three different-coloured houses. Each house hosts one cat a
vaieri [72.5K]

Answer:

1) A is a cat; B is a dog; C is a cat; D is a dog; E is a dog; F is a cat

2) A lives with B in a yellow house; C lives with D in a blue house; E lives with F in a red house.

Step-by-step explanation:

Step 1: First we identify the animals as cats or dogs

A is a cat

B is a Dog

Since B can live with C, C is a cat

Since D can live with A, D is a dog

F is a cat since it can live with D

E is therefore, a dog

Step 2: We then identify the house each two animals live in pairs of a cat and a dog

D lives in a blue house

A lives in a yellow house since it does not live with D or in a red house

C lives with D in a blue house since D does not live with either A or F

E lives in a red house since it does not live with A or in a yellow house

F lives with E in a red house since E does not live with A

Therefore, B lives with A in a yellow house

5 0
2 years ago
What is the product (6r-1)(-8r-3)
eimsori [14]
Use the FOIL method (First, Outside, Inside, Last)

6r(-8r) = -48r²
6r(-3) = -18r
-1(-8r) = 8r          (note: two negatives multiplied together = positive answer)
-1(-3) = 3

-48r² - 18r + 8r + 3

Combine like terms:


-48r² - 18r + 8r + 3

-48r² - 10r + 3


-48r² - 10r + 3 is your answer

hope this helps
6 0
2 years ago
A group pre-orders 9 tickets for a sightseeing tour, even though they don't have the money to pay for them yet. Each ticket cost
MissTica
9x$32 + 15 is the total debt. 
which would be $303.

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2 years ago
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