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ch4aika [34]
2 years ago
7

A cereal company fills boxes with 16 ounces of cereal. The acceptable percent error in filling a box is 2.5%. Find the least and

the greatest acceptable weights. Show your work please
Mathematics
1 answer:
Ket [755]2 years ago
8 0
If the acceptable percent error is 2.5%, then the amount it can be over or under 16 oz is 0.4oz.
16 + 0.4
16 - 0.4
16.4 is the greatest, 15.6 is the least
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A small country had a population of 8.4 x 10^8 in 2010. Since then, the original population has doubled, and an additional 3.7 x
Mamont248 [21]

I'm not 100% sure because it is rare to ask about adding scientific notation but I would answer it like this:

8.4x10^8 +3.7x10^9=

12.1 x 10^17

final answer

4 0
2 years ago
Suppose you have 20 coins that total $3.00. Some coins are nickels and some are quarters. Which of the following pairs of equati
shusha [124]

Answer: D. n + q = 20

5n + 25q = 300

Step-by-step explanation:

Let n represent the number of nickels that you have.

Let q represent the number of quarters that you have.

Suppose you have 20 coins. It means that

n + q = 20

The total value of the coins is $3. The value of a quarter is $0.25 and the value if a nickel is $0.05. Therefore, the equation would be

0.05n + 0.25q = 3

Multiplying both sides of the equation by 100, it becomes

5n + 25q = 300

The correct option is

D. n + q = 20

5n + 25q = 300

6 0
2 years ago
Which runner set the fastest pace? Explain.
Maru [420]

Um... you can't see what you need to solve the problem in the picture. Take a picture of the chart.

6 0
2 years ago
Read 2 more answers
Given matrix A below, and that A = B, find the value of the elements in B. A = 9 −2 3 2 17 0 3 22 8 b11 = b12 = b13 = b21 = b22
GuDViN [60]

Answer:

b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8

Step-by-step explanation:

Consider the given matrix

A=\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]

Let matrix B is

B=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]

It is given that

A=B

\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]

On comparing corresponding elements of both matrices, we get

b_{11}=9,b_{12}=-2,b_{13}=3

b_{21}=2,b_{22}=17,b_{23}=0

b_{31}=3,b_{32}=22,b_{33}=8

Therefore, the required values are b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8.

3 0
2 years ago
Read 2 more answers
Suppose a research paper states that the distribution of the daily sea-ice advance/retreat from each sensor is similar and is ap
Luda [366]

Answer:

The value of the parameter is λ is 0.03553357

Step-by-step explanation:

Consider the provided function.

f(x) = 0.5\lambda e^{-\lambda |x|} for −∞ < x < ∞.

It is given that standard deviation is given as 39.8 km.

Now we need to calculate the value of parameter λ.

The general formula for the probability density function of the double exponential distribution is: f(x)=\frac{e^{-|\frac{x-\mu}{\beta}|}}{2\beta}

Where μ is the location parameter and β is the scale parameter.

Compare the provided equation with the above formula we get.

\lambda=\frac{1}{\beta} and μ = 0.

Standard deviation = √2β

S.D=\sqrt{2} \beta\\\beta=\frac{39.8}{\sqrt{2}}\\\beta=28.1424

Now substitute the value of β in \lambda=\frac{1}{\beta}.

\lambda=\frac{1}{28.1424}=0.03553357

Hence, the value of the parameter is λ is 0.03553357

3 0
2 years ago
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