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2 years ago

9

Stephanie has a $40 balance on her credit card. She makes two additional charges to pay $20 for gas and $25 for parking. Then sh

e makes a credit card payment of $30.
What is her remaining balance?

2 answers:

nikdorinn [45]2 years ago

7 0

Answer:

She should have $25 left

Step-by-step explanation:

It she has a total of $40 and you take away the $20 she spent of gas and the $25 she spent for parking she would have -$5 but since she paid $30 back on the card she has a balance of $25

77julia77 [94]2 years ago

3 0

She should have a balance of 25

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Answer:

a. $P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

b. $E(x) = 0.3$

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Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

$P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\$

For binomial distribution:

$E(x)=np\\S(x)=\sqrt{np(1-p)}$

Therefore, the company can expect to win 0.3 bids and it is calculated as:

$E(x) = np = 3*0.1 = 0.3$

Additionally, the standard deviation of the number of bids won is:

$S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196$

Finally, the probability to won 1, 2 or 3 bids is equal to:

$P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001$

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$E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000$

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

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Answer:

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Part b) The linear equation is equal to $y=21.2x+3,090$

Part c) The tuition would be $\$3,238.4$ in 2,017

Step-by-step explanation:

step 1

<em>Find the slope m</em>

Let

x-----> the year after 2,010

y-----> the tuition

we have

For the year 2,010

$x=0\ years$

For the year 2,015

$x=(2,015-2,010)=5\ years$

so

$A(0,3,090), B(5,3,196)$

Calculate the slope

$m=\frac{(3,196-3,090)}{(5-0)}=21.2\frac{\$}{year}$

step 2

<em>Find the linear equation</em>

with the slope m and the point A find the linear equation

$y-y1=m(x-x1)$

substitute the values

$y-3,090=21.2(x-0)$

$y=21.2x+3,090$ -------> linear equation that would predict tuition for any year after 2010

step 3

Assuming the linear trend remained constant, what would tuition be in 2017

so

For $x=(2,017-2,010)=7\ years$

substitute in the linear equation

$y=21.2(7)+3,090=\$3,238.4$

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2 years ago