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Amiraneli [1.4K]
2 years ago
10

Mr. Smith had 33 dozen cans. He sold 340 of them at 15$ each. He sold the remaining cans at a discount of 20% each. How much mon

ey did he collect from selling the cans.
Mathematics
1 answer:
iren2701 [21]2 years ago
3 0

Answer:

Mr. Smith collects $5748 from selling the can.

Step-by-step explanation:

Given total number of cans = 33\times12=396

Selling price of one can = $15.

\therefore \textrm{Selling price of 340 cans} = \textrm {selling price of one can} \times \textrm {number of cans}=15\times340=\$5100

Now remaining number of cans = total number of cans - sold number of cans =396-340=54

For remaining number of cans he gives a discount of 20% each,

∴ Selling price of one can = 15-\frac{15\times20}{100}=15-3=12

∴ Selling price of 54 cans = \textrm{selling price of one can} \times \textrm{number of cans}=12\times54=\$648

So total money he earns =  \$5100+\$648= \$5748.

Thus Mr. Smith earns $5748 by selling the cans.

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Step-by-step explanation:

Please see the attached pictures for the full solution.

Further explanantion (2nd image):

The reason why the ratio of A: C is equal to the ratio if 2A: 2C is that the number of parts of A and C is equal, which is 2 parts. If I were to divide both 2A and 2C by 2 to find the ratio of A: C, I would obtain 15: 15/2. However, ratios are expressed as whole numbers and thus, we would multiply the whole ratio by 2 again and the answer would still be 30: 15. This ratio is not in the simplest form since both can be divided by 15. Thus, dividing both sides of the ratio by 15 will leave us with the final answer of

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☆ An alternative method is to simplify the ratio 3B: 2C at the beginning.

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