Solution -
drawing a perpendicular from AQ to TS, we get a right angle triangle AQT
Using Pythagoras Theorem,
AT² = AQ² + QT²
⇒26² = 24² + QT² (∵ Due to symmetry AQ = RS)
⇒QT² = 676-576 = 100
⇒QT = 10
As TS = QT + QS = 12 + 10 = 22 ( ∵ Due to symmetry AR = QS )
∴ TS = 22 (ans)
Hey there!
If these hexagons are congruent, then each angle is congruent to the one that is in the same position as it is. In this case, I and V are congruent because they are both last. K and U are congruent because they are both second to last.
While looking over the answer options, you should be able to see that Angle J and Angle S is the only answer with angles that match up, because they are both the first angle in the set.
I hope this helps!
We can used the Simpson's Rule says to approximate the area under a given curve using the following formula:
<span>(Δx/3)[f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + ... + 2f(xn-2) + 4f(xn-1) + f(xn)] </span>
<span>The pool is divided into 8 subintervals. We integrate the given function from 0 to 24, while the graph provides values of f(x) at 7 different points. The first value given, 6.2, is NOT f(0). It is f(3). Using Simpson's Rule, and dividing the lake of 24 meters into 8 subintervals, we write the equation: </span>
<span>area = (3/3)[f(0) + 4f(3) + 2f(6) + 4f(9) +2f(12) + 4f(15) + 2f(18) + 4f(21) + f(24)] </span>
<span>Pool area = 0 + 4(6.2) + 2(7.2) +4(6.8) + 2(5.6) + 4(5.0) +2(4.8) +4(4.8) + 0 = 126.4 m^2 </span>
<span>Rounding to the nearest square meter, the area of the lake is approximately 126 m^2 </span>
Answer:
<em>(A). x ≥ </em>
<em> and x ≤ - </em>
<em> </em>
Step-by-step explanation:
5x - 4 ≥ 12 ⇔ 5x ≥ 16 ⇒ <em>x ≥ </em><em> </em>
<em>and </em>
12x + 5 ≤ - 4 ⇔ 12x ≤ - 9 ⇔ 4x ≤ - 3 ⇒ <em>x ≤ - </em>
"Alaina’s sugar cookie recipe calls for 2 1/4
cups of flour per batch. If she wants to make 2/3
a batch of cookies, how much flour should she use?"
1 1/2 Cups, if she wants to make less than the original recipe, she would need less flour, you have to divide.
