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IgorC [24]
2 years ago
15

Ivan and Tanya share £150 in the ratio 4:1 how much more Ivan has then tanya

Mathematics
2 answers:
blsea [12.9K]2 years ago
5 0

Answer:

90

Step-by-step explanation:

Since the ratio is 4:1 there are 5 (4+1) parts you should divide it into.

150 ÷ 5 = 30

30 = 1 part

30 × 4 = 120

Ivan has 120 while Tanya has 30. to find the difference you subtract the two.

120 - 30 = 90

Alexeev081 [22]2 years ago
3 0

Hey!

--------------------------------------------------------

Solution:

Ratio is 4/1

Add.

4 + 1 = 5

Divide.

150 / 5 = 30

Multiply for Ivan.

30 x 4 = 120

30 x 1 = 30

Check.

120 + 30 = 150

Subtract.

120 - 30 = 90

--------------------------------------------------------

Answer:

Ivan has £90 more than Tanya has!

--------------------------------------------------------

Hope This Helped! Good Luck!

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A travel agency charges $64 for each bus ticket and $82 for each train ticket. Aaron has $520 to purchase tickets. If he buys 3
Firlakuza [10]

Answer:

The total number of train tickets Aaron can buy=4

Step-by-step explanation:

a). Determine first expression

Let the number of each mode of transport be as follows;

bus ticket=b

train ticket=t

b). Determine the second expression

Let the total cost be expressed as shown;

total cost=(cost per bus ticket×number of bus tickets)+(cost per train ticket×number of train tickets)

where;

total cost=$520

cost per bus ticket=$64

number of bus tickets=b=3

cost per train ticket=$82

number of train tickets=t

replacing;

(64×3)+(82×t)=520

192+82 t=520

82 t=520-192

82 t=328

t=328/82=4

t=4

The total number of train tickets Aaron can buy=4

8 0
2 years ago
An equation was created for the line of best fit from actual enrollment data. It was used to predict the dance studio enrollment
stealth61 [152]

Answer:  First option is correct.

Step-by-step explanation:

Enrollment month   Actual   Predicted   Residual

January                   500           8                4

February                 400           15              -1

March                     550            15              -1

April                         13              12              -1

May                         16              17              -1

June                        14              15              -1

Since we know that

Residual value = Actual value - Predicted value

Sum of residuals is given by

4-1-1+1-1-1=1

since we can see that sum of residual is more than 0.

So, it can't be a good fit .

Hence, No, the equation is not a good fit because the sum of the residuals is a large number.

Therefore, First option is correct.

6 0
2 years ago
An experiment was performed to compare the abrasive wear of two different laminated materials. Twelve pieces of material 1 were
vladimir1956 [14]

Answer:

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

There is  significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units

Step-by-step explanation:

<u>Step:-(1)</u>

Given data the samples of material 1 gave an average (coded) wear of 85 units with a sample standard deviation of 4

Mean of the first sample x₁⁻ =85

standard deviation of the first sample S₁ = 4

Given data the samples of material 2 gave an average of 81 and a sample standard deviation of 5.

Mean of the first sample x₂⁻ =81

standard deviation of the first sample S₂ = 5

<u>Step :-2</u>

<u>Null hypothesis: H₀:</u> there is no significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

<u>Alternative hypothesis :H₁: </u>there is  significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Assume the populations to be approximately normal with equal variances.σ₁² =σ₂²

The test statistic

                     Z= \frac{x_{1} -x_{2} }{\sqrt{\frac{S^2_{1} }{n_{1} } +\frac{S^2_{2} }{n_{2} }  } }

Given  n₁=n₂=60.

                    Z= \frac{85-81 }{\sqrt{\frac{(4)^2 }{60 } +\frac{5^2 }{60}  } }

On calculation, we get

                   Z =   \frac{4}{\sqrt{0.6833} }

                   z = 4.8389

The tabulated value Z =1.96 at 0.05 level of significance.

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

Conclusion:-

there is  significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units.

3 0
2 years ago
The letters that spell TENNESSEE are each written on separate tiles lying facedown on a table. A tile is selected at random, the
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Answer:

There are 9 Letters in TENNESSEE. And 4 letters are E.

So the correct probability is 4/9.

6 0
2 years ago
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The automatic car wash at a service station can wash 96 cars over a 4-hour period. What is the average number of cars that can b
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Answer:

Divide 96/4 to get how many cars can be washed within a single hour. Cut that in half to get 12.

Step-by-step explanation:

96÷4=24 cars/hr

24÷2=12 Cars for every 30 minutes.

7 0
2 years ago
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