All categories

2 years ago

The amount of water flowing into a tank doubles every minute. The tank if full in an hour. When is the tank half full.

1 answer:

7 0

Since the water in the tank is doubling each minute, that means the minute before the tank was full, it was half full.
If it fills in an hour, which is 60 minutes, than that is double what it was 1 minute ago.

The invert of doubling is halving.
The tank was half full a minute before it was full.
It was full after 60 minutes.
This means it was half full after 59 minutes.

Answer:
The tank was half full after 59 minutes.

Hope this helps!

You might be interested in

The polynomial 24x3 − 54x2 + 44x − 99 is factored by grouping. 24x3 − 54x2 + 44x − 99 24x3 + 44x − 54x2 − 99 4x(____) − 9(____)

Alenkasestr [34]

Answer: $6x^2+11$

Step-by-step explanation:

Given the polynomial of degree 3:

$24x^3 - 54x^2 + 44x -99$

You can observe make two groups or two terms each:

$(24x^3 + 44x) - (54x^2 + 99)$

The Greatest Common Factor (GCF), is the highest number that divides into two or more numbers without leaving remainder.

You can observe that the GCF of both set are factored out ( $4x$ and $9$ ), then, you can find the common factor that is missing from both sets of parentheses with this procedure:

$(\frac{24x^3}{4x}+\frac{44x}{4x})-(\frac{54x^2}{9}+\frac{99}{9})=(6x^2+11)-(6x^2+11)$

You can observe that the common factor that is missing from both sets of parentheses is:

$6x^2+11$

3 0

1 year ago

Find c, yenvelope(x,t), and ycarrier(x,t). express your answer in terms of a, k1, k2, x, t, ω1, and ω2. separate the three parts

steposvetlana [31]

Answer:

$C,Y_{envelope}(x,t), Y_{carrier}(x,t)=2A, \cos ((k_1-k_2)x/2-(\omega_1 -\omega_2)t / 2 ) , \sin ((k_1+k_2)x / 2 - (\omega_1 +\omega_2)t / 2 )$

Step-by-step explanation:

Given

$Y_1(x,t)=A \sin(K_1x- \omega _1 t)\\\\Y_2(x,t)=A \sin(K_2x- \omega _2 t)$

using a trigonometrical identity

sin p + sin q = 2 sin ( p+q/2) cos ( p-q/2)

and here the condition is

the choice is in between sinax and cosax

where a > b

so we get using above equation

$C,Y_{envelope}(x,t), Y_{carrier}(x,t)=2A, \cos ((k_1-k_2)x/2-(\omega_1 -\omega_2)t / 2 ) , \sin ((k_1+k_2)x / 2 - (\omega_1 +\omega_2)t / 2 )$

4 0

2 years ago

Dan is using tiles to add Negative 8 + 6. He begins with the tiles shown below. 8 negative tiles. What is the sum of Negative 8

navik [9.2K]

The answer is -2

-8+6=-2

4 0

2 years ago

Read 2 more answers

N triangle xyz, m∠z > m∠x m∠y. which must be true about △xyz?

liubo4ka [24]

The choices are the below that can be found elsewhere:

m∠X + m∠Z < 90°

m∠Y > 90°

∠X and∠Y are complementary

m∠X + m∠Y < 90°

Since the given is m<Z > m<X +m<Y and the sum of measure of angles of a triangle is equal 180 degrees so from this result that the last one choice need being true sure so m<X +m<Y < 90°

4 0

2 years ago

Read 2 more answers

Tania has 56 liters of milk. She uses the milk to make muffins and cakes. Each batch of muffin requires 7 liters of milk and eac

mihalych1998 [28]

Write the inequalities that are given by the :

x: the number of batches of muffins

y: the number of batches of cakes

Each batch of muffin requires 7 liters of milk and each batch of cakes require 4 liters of milk.

=> liters of milk use = 7x + 4y

Tania has 56 liters of milk.=> 7x + 4y ≤ 56

Which means that the amount of muffins and cakes made are limited by the availability of 56 liter of milk.

The inequality 7x + 4y ≤ 56 is graphed by drawing the line 7x + 4y = 56 and shading the region below that line.

The line 7x + 4y = 56 has these x and y intercepts:

y-intercept: x =0 => 4y = 56 => y = 56/4 => 14 => point (0,14)

x-intercept => y = 0 => 7x = 56 => x = 56/7= 8 => point (8,0)

So, the line passes through the poins (0,8) and (14,0) and the solution region is below that line.

Also, you know that x and y are restricted to be positive or zero =>

x ≥ 0

y ≥ 0.

So, the solution region is restricted to the first quadrant.

That implies that the answer is:

Line joining ordered pairs 0, 14 and 8, 0. Shade the portion of the graph below this line which lies within the first quadrant

4 0

2 years ago