Answer:
B. $3927.54
Step-by-step explanation:
just took the test
Answer:
The answer to your question is 
Step-by-step explanation:
To solve this problem we must use proportions
92 ---------------------- 100
x ---------------------- 20
Use cross multiplication to solve this proportion
x = 
Simplify 
= 
Substitute this value
To evaluate 17 int (sin^2 (x) cos^3(x))
From Trig identity. Cos^2(x) + sin^2(x) =1. Cos^2(x) = 1 - sin^2 (x)
Cos^3(x) = cosx * (1 - sin^2 (x)) = cosx - cosxsin^2x
So we have 17 int (sin^2x(cosx - cosxsin^2x))
int (sin^2x(cosx)dx - int (sin^4xcosx)dx. ----------(1)
Let u = sinx then du = cosxdx
Substituting into (1) we have
int (u^2du) - int (u^4du)
u^3/3 - u^5/5
Substitute value for u we have
(sinx)^3/3 - (sinx)^5/5
Hence we have 17 [ sin^3x/3 - sin^5x/5]
It increases at T because the behavior increased its speed
