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Leto [7]
2 years ago
11

What is the expanded form of this number? 503.208 (Trying to help my sister do math!)

Mathematics
1 answer:
Blababa [14]2 years ago
3 0

Answer:

500+3+ .200+.008

Step-by-step explanation:

You add 500 and 3 then after you get your number add .200 lastly add .008.

when expanding numbers you need to know what place value it's in so that you k ow where to put the zeros.

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Given: WXYZ is a parallelogram, ZX ≅ WY
Mrrafil [7]

Answer:

Step-by-step explanation:

Given: WXYZ is a parallelogram, ZX ≅ WY

Prove: WXYZ is a rectangle

Proof:

Step 1. WXYZ is a parallelogram and ZX ≅ WY (Given)

Step 2. ZY ≅ WX (Opposite sides of parallelogram are congruent)

Step 3. YX ≅ YX  (Reflexive Property)

Step 4. Consider △ZYX and △WXY, we have

ZX ≅ WY (Given)

ZY ≅ WX (Opposite sides of parallelogram are congruent)

YX ≅ YX  (Reflexive Property)

Thus, by SSS rule, △ZYX ≅ △WXY

Step 5. By CPCTC, ∠ZYX ≅ ∠WXY

Step 6.  m∠ZYX ≅ m∠WXY (Definition of congruency)

Step 7.  m∠ZYX + m∠WXY = 180° ( consecutive ∠s in a parallelogram are supplementary)

Step 8. m∠ZYX + m∠ZYX = 180° (Substitution)

Step 9. 2(m∠ZYX) = 180° (Simplification)

Step 10.  m∠ZYX = 90° (Dividing property of equality)

Step 11. WXYZ is a rectangle (Rectangle angle theorem)

Hence proved.

5 0
2 years ago
Two movie tickets and 3 snacks are $24. Three movies tickets and 4 snacks are $35. How much is a movie ticket and how much is a
Vsevolod [243]

Answer: A movie ticket is $9 while a snack is $2

Step-by-step explanation: We shall let a movie ticket be m while a snack is s. So, from the clues given, if two movie tickets and three snacks cost $24, we can write it as the following expression;

2m + 3s = 24

Also if three movie tickets and four snacks cost $35, we can as well write another expression as follows;

3m + 4s = 35.

Now we have a pair of simultaneous equations which are

2m + 3s = 24 ----------(1)

3m + 4s = 35 ----------(2)

We shall solve this by using the elimination method, since none of the variables has a coefficient of 1. We'll start by multiplying equation (1) by 3 and multiplying equation (2) by 2 (so as to eliminate the m variable)

2m + 3s = 24 -------- x3

3m + 4s = 35 ---------x2

We now arrive at the following

6m + 9s = 72--------(3)

6m + 8s = 70--------(4)

Subtract equation (4) from equation (3) and we arrive at

s = 2

Having determined that s equals 2 we can now substitute for the value of a into equation (1)

2m + 3s = 24

2m + 3(2) = 24

2m + 6 = 24

Subtract 6 from both sides of the equation

2m + 6 - 6 = 24 - 6

2m = 18

Divide both sides of the equation by 2

m= 9

Therefore one movie ticket costs $9 while one snack costs $2

6 0
2 years ago
Chris tried to rewrite the expression \left( 4^{-2} \cdot 4^{-3} \right)^{3}(4
crimeas [40]

We have been given an expression \left( 4^{-2} \cdot 4^{-3} \right)^{3}. We have been given steps how Chris tried to solve the given expression. We are asked to choose the correct option about Chris's work.

Let us simplify our given expression.

Using exponent property, a^m\cdot a^n=a^{m+n}, we cab rewrite our given expression as:

\left( 4^{-2+(-3)} \right)^{3}

\left( 4^{-5} \right)^{3}

Now we will use exponent property (a^m)^n=a^{m\cdot n}to further simplify our expression.

\left( 4^{-5} \right)^{3}= 4^{-5\cdot 3}

\left( 4^{-5} \right)^{3}= 4^{-15}

Therefore, Chris made mistake in step 2.

8 0
2 years ago
Ten people, including Fred, are in the Jazz Club. They decide to form a 3-person steering committee. How many possible committee
Anastasy [175]

Answer:

30

Step-by-step explanation:

7 0
2 years ago
Which of the following events are equal? (a) A = {1,3}; (b) B = {x | x is a number on a die }; (c) C = {x | x2 −4x +3=0 }; (d) D
rosijanka [135]

Answer:

A and C

Step-by-step explanation:

To determine which events are equal, we explicitly define the elements in each set builder.

For event A

A={1.3}

for event B

B={x|x is a number on a die}

The possible numbers on a die are 1,2,3,4,5 and 6. Hence event B is computed as

B={1,2,3,4,5,6}

for event C

C=[x|x^{2}-4x+3]\\solving  x^{2}-4x+3\\x^{2}-4x+3=0\\x^{2}-3x-x+3=0\\x(x-3)-1(x-3)=0\\x=3 or x=1

Hence the set c is C={1,3}

and for the set D {x| x is the number of heads when six coins re tossed }

In the tossing a six coins it is possible not to have any head and it is possible to have head ranging from 1 to 6

Hence the set D can be expressed as

D={0,1,2,3,4,5,6}

In conclusion, when all the set are compared only set A and set C are equal

5 0
2 years ago
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