Answer:
y = 16x/65
Step-by-step explanation:
Given:
Triangle ABE is similar to triangle ACD. AED and ABC are straight lines
EB and DC are parallel
The area of quadrilateral BCDE = xcm²
The area of triangle ABE = ycm²
Find attached the diagram from the above information.
In similar triangles, the ratio of their corresponding angles are equal.
Also, the ratio of the area of the two triangles = square of ratio of the corresponding sides of the two triangles.
Area ∆ACD/area of ∆ABE = (DC/EB)²
Area ∆ACD/area of ∆ABE = [(area of quadrilateral BCDE +
area of ∆ABE)]/(area of ∆ABE)
(x+y)/y = (DC/EB)²
(x+y)/y = (9/4)²
x+y = (81/16)y
x = (81/16)y - y
x = (81y - 16y)/16
x = 65y/16
Making y subject of formula
16x = 65y
y = 16x/65
An expression for y in terms of x:
y = 16x/65
The answer is 8 marbles. 6*8=48. 48(ednas marbles) + 8(sam's marbles)=56.
The sum of a straight angle is 180°
So 77+x=180
Subtract 77 from both sides and the equation is
x=77
The measure of the other angle is 77°
The cost of bananas = $ 3.48
This can be written as :
this number written in expanded notation as : (3 × 1) + (4 × 0.1) + (8 × 0.01)
3+0.4+0.08 = 3.48
Hence, 1st option is correct.
Answer:
See Explanation
Step-by-step explanation:
Given
--- Number of tryouts
Required
Determine the average distance
<em>This question has missing details, as the distance he hits the ball in each tryout is not given. However, I'll give a general explanation.</em>
<em></em>
The mean is calculated as:
means the sum of the distance in each tryout.
Assume that the distance in the 10 tryouts are: 
So, the mean is:
<em>So, the average distance is 6.5</em>
