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2 years ago

11

Jenny has 550g of flour. She needs 0.5kg of flour for a recipe.when she has made her recipe,has many grams of flour will she hav

e left

1 answer:

DIA [1.3K]2 years ago

8 0

She will have 50 grams left

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Find the percentage change between two numbers if the original number was 150 and now is 330.

bearhunter [10]

Answer:

0.45

Step-by-step explanation:

8 0

2 years ago

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Eli invested $ 330 $330 in an account in the year 1999, and the value has been growing exponentially at a constant rate. The val

Cloud [144]

Answer:

The value of the account in the year 2009 will be $682.

Step-by-step explanation:

The acount's balance, in t years after 1999, can be modeled by the following equation.

$A(t) = Pe^{rt}$

In which A(t) is the amount after t years, P is the initial money deposited, and r is the rate of interest.

$330 in an account in the year 1999

This means that $P = 330$

$590 in the year 2007

2007 is 8 years after 1999, so P(8) = 590.

We use this to find r.

$A(t) = Pe^{rt}$

$590 = 330e^{8r}$

$e^{8r} = \frac{590}{330}$

$e^{8r} = 1.79$

Applying ln to both sides:

$\ln{e^{8r}} = \ln{1.79}$

$8r = \ln{1.79}$

$r = \frac{\ln{1.79}}{8}$

$r = 0.0726$

Determine the value of the account, to the nearest dollar, in the year 2009.

2009 is 10 years after 1999, so this is A(10).

$A(t) = 330e^{0.0726t}$

$A(10) = 330e^{0.0726*10} = 682$

The value of the account in the year 2009 will be $682.

4 0

2 years ago

Find all polar coordinates of point P = (6, 31°).

wel

as far as I can tell, is just a matter of going around the circle many or infinite times around.

so 6,31° is the first point, the next point will be one-go-around, 6, 31+360 => 6, 391°

then the next will be 6, 391+360 => 6, 751° and so on.

so we can say is (6, 31° ±360°n), n ∈ ℤ.

6 0

2 years ago

PLEASE HELP!!! ASAP The function graphed approximates the height of a rock, in meters, x seconds after it falls from a cliff

nasty-shy [4]

The vertical numbers are the distance and the horizontal numbers are the time in seconds.

Look at where the line is located at the number 20.

It si between the 2 and the 3 on the horizontal line, but you can see it is closer to the 2 than it is the 3, so the time would be 2.2s

8 0

2 years ago

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Simplify the expression to a form in which 2 is raised to a single integer power. fraction numerator open parentheses 2 to the p

anzhelika [568]

Answer:

2^27

Step-by-step explanation:

Given the following expression:

[(2^10)^3 x (2^-10)] ÷ 2^-7

This can be easily simplified. Let us simplify the numerator first. To do that, we have

(2^10)^3 making use of the power rule of indices that says:

(A^a)^b = A^ab where a and b are powers, we have:

2^(10x3) = 2^30

Therefore the numerator becomes:

2^30 x 2^-10. Also making use of the multiplication rule that says:

A^a x A^b = A^(a + b), we have

2^30 x 2^-10 = 2^(30 – 10) = 2^20.

Now we have:

(2^20) ÷ (2^-7)

To simplify this, we need the division rule of indices which says:

A^a ÷ A^b = A^(a – b)

Therefore we have:

(2^20) ÷ (2^-7) = 2^[20 – (–7)] = 2^(20+7) = 2^27

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2 years ago