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Scorpion4ik [409]

2 years ago

14

Kat is painting the edge of a triangular stage prop with reflective orange paint. The lengths of the edges of the triangle are (

3x-4) feet, (x2 - 1) feet, and (2x2 -15) feet. what is the perimeter of a triangle if X equals four

1 answer:

nordsb [41]2 years ago

8 0

First, let's convert X into 4

(3*4 - 4)ft, (4*2 - 1)ft, (2*4*2 - 15)ft

Now lets simplify this a little

(12 - 4)ft, (8 - 1)ft, (16 - 15)ft

Awesome now lets finish up

8 x 9 x 1 / 2 = 36

The answer should be 36ft. Unless I did my math wrong.

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The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev

Nataliya [291]

Answer:

(a) Probability that a sheet selected at random from the population is between 30.25 and 30.65 inches long = 0.15716

(b) Probability that a standard normal random variable will be between .3 and 3.2 = 0.3814

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with;

Mean, $\mu$ = 30.05 inches and Standard deviation, $\sigma$ = 0.2 inches

Let X = A sheet selected at random from the population

Here, the standard normal formula is ;

Z = $\frac{X - \mu}{\sigma}$ ~ N(0,1)

(a) <em>The Probability that a sheet selected at random from the population is between 30.25 and 30.65 inches long = P(30.25 < X < 30.65) </em>

P(30.25 < X < 30.65) = P(X < 30.65) - P(X <= 30.25)

P(X < 30.65) = P( $\frac{X - \mu}{\sigma}$ < $\frac{30.65 - 30.05}{0.2}$ ) = P(Z < 3) = 1 - P(Z >= 3) = 1 - 0.001425

= 0.9985

P(X <= 30.25) = P( $\frac{X - \mu}{\sigma}$ <= $\frac{30.25 - 30.05}{0.2}$ ) = P(Z <= 1) = 0.84134

Therefore, P(30.25 < X < 30.65) = 0.9985 - 0.84134 = 0.15716 .

(b)<em> Let Y = Standard Normal Variable is given by N(0,1) </em>

<em> Which means mean of Y = 0 and standard deviation of Y = 1</em>

So, Probability that a standard normal random variable will be between 0.3 and 3.2 = P(0.3 < Y < 3.2) = P(Y < 3.2) - P(Y <= 0.3)

P(Y < 3.2) = P( $\frac{Y - \mu}{\sigma}$ < $\frac{3.2 - 0}{1}$ ) = P(Z < 3.2) = 1 - P(Z >= 3.2) = 1 - 0.000688

= 0.99931

P(Y <= 0.3) = P( $\frac{Y - \mu}{\sigma}$ <= $\frac{0.3 - 0}{1}$ ) = P(Z <= 0.3) = 0.61791

Therefore, P(0.3 < Y < 3.2) = 0.99931 - 0.61791 = 0.3814 .

3 0

2 years ago

Most US adults have social ties with a large number of people, including friends, family, co-workers, and other acquaintances. I

xxTIMURxx [149]

Answer:

$t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971$

$p_v =2*P(t_{(1699)}>1.971)=0.049$

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=669$ represent the sample mean

$s=732$ represent the sample standard deviation

$n=1700$ sample size

$\mu_o =68$ represent the value that we want to test

$\alpha=0.$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:

Null hypothesis: $\mu = 634$

Alternative hypothesis: $\mu \neq 634$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=1700-1=1699$

Since is a two sided test the p value would be:

$p_v =2*P(t_{(1699)}>1.971)=0.049$

Conclusion

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

3 0

2 years ago

What algebraic expression could represent the average of 2x, x + 3, and 6x?

Gre4nikov [31]

Answer:

(5x = 2 = 3 +8a

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The perimeter of the norwegian flag is 190 inches. What are the dimensions of the flag?

mario62 [17]

<span>The dimensions are 40 inches by 55 inches.

Explanation<span>:
We know that perimeter is the sum of all of the sides. Since this is rectangular, opposite sides are equal. This gives us
y+11/8y+y+11/8y=190.

Combining like terms, we have
2y+22/8y=190.

Writing 22/8 as a mixed number, we have
2y+2 3/4y=190
4 3/4y=190.

Divide both sides by 4 3/4:
(4 3/4y)</span></span>÷<span><span>(4 3/4)=190</span></span>÷<span><span>(4 3/4)
y=190</span></span>÷<span><span>(4 3/4).

Convert the mixed number to an improper fraction:
y=190</span></span>÷<span><span>(19/4).

To divide fractions, flip the second one and multiply:
y=190*(4/19)=760/19=40.

Since y=40, 11/8y=11/8(40)=440/8=55.</span></span>

8 0

2 years ago

The organizers of a talent show have budgeted $1800 to buy souvenir clothing to sell at the event. They can buy shirts for $10 e

ki77a [65]

Let s represent number of shirts and h represent number of hats.

We have been given that the organizers of a talent show have budgeted $1800 to buy souvenir clothing to sell at the event. They can buy shirts for $10 each and hats for $8 each.

The cost of s shirts would be $10s$ and cost of h hats would be $8h$ . The cost of s shirts and h hats should be less than or equal to 1800. We can represent this information in an inequality as:

$10s+8h\leq 1800$

We are also told that organizers plan to buy at least 5 times as many shirts as hats. This means that number of shirts should be greater than or equal to 5 times hats. We can represent this information in an inequality as:

$s\geq 5h$

Therefore, the second inequality should be $s\geq 5h$ and option C is the correct choice.

6 0

2 years ago