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LUCKY_DIMON [66]
2 years ago
15

tom and barb have only nickels and dimes. barb has 75 cents and Tom has 90 cents. both have the same number of coins and Tom has

the same number of dimes as barb has nickels. how many nickels does barb have?
Mathematics
2 answers:
Mazyrski [523]2 years ago
8 0

Answer:

Barb have 4 nickels.

Step-by-step explanation:

Tom and Barb have nickels and dimes only.

Let numbers of nickels and dimes Tom have = n and d

Let numbers of nickels and dimes Barb have = n' and d'

Both have same number of coins then equation will be  

n + d = n' + d' ------(1)

Tom has same number of dimes as Barb has nickels

d = n'

By replacing d = n' in equation (1)

n + n' = n' + d'

n = d'

It has been given in the question that Barb has 75 cents and Tom has 90 cents in the form of nickels and dimes.

0.05n + 0.10d = 0.75

Dividing this equation by 0.05

n + 2d = 15-------(2)

0.05n' + 0.10d' = 0.90

By diving this equation by 0.05

n' + 2d' = 18

Since n' = d and d' = n

Then d + 2n = 18 -------(3)

Now we multiply equation (2) by 2 and subtract it by equation (3)

2(n + 2d) - (d + 2n) = 15×2 - 18

2n + 4d - d - 2n = 30 - 18

3d = 12

d = 4

Since d = n'

So n' = 4

Therefore, Barb have 4 nickels.

Galina-37 [17]2 years ago
4 0
They both he 9 coin barb has 3 nickels and 6 dimes
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In your sock drawer you have 5 blue, 7 gray, and 2 black socks. Half asleep one morning you grab 2 socks at random and put them
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The question is incomplete! The complete question along with answers and explanation is provided below!

In your sock drawer you have 5 blue, 7 gray, and 2 black socks. Half asleep one morning you grab 2 socks at random and put them on. Find the probability you end up wearing the following socks. (Round your answers to four decimal places.)

a) 2 blue socks

b) no gray socks

c) at least 1 black sock

d) a green sock

e) matching socks

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a) P(2 blue socks) = 0.1099 = 10.99%

b) P(no gray socks) = 0.2307 = 23.07%

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d) P(green sock) = 0%

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Given Information:

5 Blue socks

7 Gray socks

2 black socks

Total socks = 5 + 7 + 2 = 14

a) The probability of wearing 2 blue socks

P(2 blue socks) = P(B1 and B2)

P(B1) = no. of blue socks/total no. of socks

P(B1) = 5/14 = 0.3571

Now there are 4 blue socks remaining and total 13 socks remaining

P(B2|B1) = 4/13 = 0.3077

P(B1 and B2) = 0.3571*0.3077 = 0.1099 = 10.99%

b) The probability of wearing no gray socks

5 Blue socks + 2 black socks = 7 socks are not gray

P(no gray socks) = P(Not G1 and Not G2)

P(Not G1) = no. socks that are not grey/ total no. of socks

P(Not G1) = 7/14 = 0.5

Now there are 6 socks remaining that are not gray and total 13 socks remaining

P(Not G2 | Not G1) = 6/13 = 0.4615

P(Not G1 and Not G2) = 0.5*0.4615 = 0.2307 = 23.07%

c) The probability of wearing at least 1 black sock

5 Blue socks + 7 Gray socks = 12 socks are not black

P(at least 1 Black) = 1 - P(Not B1 and Not B2)

P(Not B1) = no. socks that are not black/ total no. of socks

P(Not B1) = 12/14 = 0.8571

Now there are 11 socks remaining that are not black and total 13 socks remaining

P(Not B2 | Not B1) = 11/13 = 0.8461

P( Not B1 and Not B2) = 0.8571*0.8461 = 0.7252

P(at least 1 Black) = 1 - P( Not B1 and Not B2)

P(at least 1 Black) = 1 - 0.7252 = 0.2748 = 27.48%

d) The probability of wearing a green sock

There are 0 green socks, therefore

P(Green) = 0/14 = 0%

e) The probability of wearing matching socks

P(Matching socks) = P(2 Blue socks) + P(2 Gray socks) + P(2 Black socks)

P(2 Blue socks) already calculated in part a

P(2 Blue socks) = P(B1 and B2) = 0.1099

For Gray socks

P(G1) = no. of gray socks/ total no. of socks

P(G1) = 7/14 = 0.5

Now there are 6 gray socks remaining and total 13 socks remaining

P(G2 | G1) = 6/13 = 0.4615

P(2 Gray socks) = P(G1 and G2) = 0.5*0.4615 = 0.2307

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P(B1) = no. of black socks/ total no. of socks

P(B1) = 2/14 = 0.1428

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P(B2 | B1) = 1/13 = 0.0769

P(2 Black socks) = P(B1 and B2) = 0.1428*0.0769 = 0.0110

P(Matching socks) = P(2 Blue socks) + P(2 Gray socks) + P(2 Black socks)

P(Matching socks) = 0.1099 + 0.2307 + 0.0110 = 0.3516 = 35.16%

7 0
2 years ago
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