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Ratling [72]
2 years ago
9

Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At t

he end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. mean = 20.45 s = .80 n = 18. If we were to conduct a test to see if the sample estimate is different from the company’s expected weight of 20 oz. at an alpha level = .05, what is (are) the critical t-value(s) for this test? Group of answer choices
Mathematics
1 answer:
VladimirAG [237]2 years ago
3 0

Answer:

Step-by-step explanation:

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Just the question about sandy))<br><br>A &amp; B
hammer [34]
A.) 50.45m + 60 = 57.95m

b.) 50.45m + 60 = 57.95m
     60 = 57.95m - 50.45m
     60 = 7.50m
     60 / 7.50 = m
     8 = m.....so the cost will be the same at 8 months

7 0
2 years ago
If f(x) = − 5, what is f(8.6)?
harina [27]
8.6 = -5 
13.6 = 0
There should be another x value in your equation above, but with what you listen this is correct.
5 0
2 years ago
Read 2 more answers
Which of the following values for m proves that 2m + 2m is not equivalent to 4m2?
Mashutka [201]
M=0 i am not sure it is right 
6 0
2 years ago
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The two lines, P and Q, are graphed below: Line P is drawn by joining ordered pairs negative 8,15 and 6, negative 12. Line Q is
andreyandreev [35.5K]

Solution:

Keep in mind ,

Equation of line joining two points (a,b) and (p,q) is given by :

     \frac{q-b}{p-a}=\frac{y-b}{x-a}

Equation of line P which is obtained by  joining  (- 8,15) and (6, - 12) is given by:  

\frac{y-15}{x+8}=\frac{-12-15}{6+8}\\\\ 14(y-15)=-27(x+8)\\\\ 14 y -210= -27 x - 216\\\\ 27 x+14 y+6=0

Equation of line Q which is obtained by  joining  (4,16) and (-9, 10) is given by:  

\frac{y-16}{x-4}=\frac{16-10}{4+9}\\\\ 13(y-16)=6(x-4)\\\\ 13 y -208= 6 x - 24\\\\ 6 x-13 y+184=0

Equation of line P and Q are

27 x+14 y+6=0-------(1)× 2

6 x-13 y+184=0-------(2)× 9

54 x + 2 8 y+12=0---(1)

54 x -117 y +1656=0----(2)

(1) - (2)

145 y= 1644

y=11.33,

27 x+14 y+6=0-------(1)×13

6 x-13 y+184=0-------(1)×14

351 x + 182 y + 78=0-----(1)

84 x - 182 y +2576=0----(2)

(1) + (2)

435 x + 2654=0

x = - 6.11

So, solution set is (-6.11, 11.33)

Option (C) is true. (−2, 4), because this point makes both the equations incorrect.


8 0
2 years ago
Craig ran the first part of a race with an average speed of 8 miles per hour and biked the second part of a race with an average
enot [183]
Then, 15 - x is the distance ran in the second part.
The time, t1, for the first part is t1 = xmi / 8mi/h
The time, t2, for the second part is t2 = (15 - x)mi / 20mi/h
The total time is t1 + t2 = 1.125 h
Then x/8 + (15 - x) / 20 = 1.125
To solve for x, multiply both sides by 40 (this is the least common multiple)
5x + 30 - 2x = 45
3x = 15

to find x divide: 15/3=5

And 15 - x = 10 mi.
First part:
Speed: 8mi/h
Distance: 5 mi
Time: 5mi/8mi/h = 5/8 h = 37.5 minutes
Second part
Speed: 20 mi/h
Distance: 10 mi
Average speed: 15mi/1.125h =13.33 mi/h
Distance: 15mi
Time: 1.125 h = 67.5 minutes 
7 0
2 years ago
Read 2 more answers
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