Answer:
c- shifted 3 units right and 4 units up
Step-by-step explanation:
In this problem, we have a quadrilateral named as ABCD. Recall that a quadrilateral is a two-dimensional shape having four sides. So, we need to identify what transformation has been performed to get A'B'C'D', which is the same quadrilateral shifted certain units right and up. So take one point, say, B, so how do we need to do to obtain point B'? well, we need to move that point 3 units right and 4 units up, but how can we know this? just count the number of squares you need to move from B to B' horizontally and vertically, which is in fact 3 units right and 4 units up.
Answer is 4 lb.,12 oz.
As one pound has 16 ounces.
When we convert the given 5 lb. into ounces we multiply it by 16.
5 lb = 5 x 16 oz
5 lb = 80 oz
When we subtract 4 oz from 80 oz
We get
80 - 4 = 76 oz
Which is
64 oz + 12 oz
(16 x 4) oz + 12 oz
Which will be
4 lb. + 12 oz
So the answer will be
4 lb., 12 oz.
Answer:
Step-by-step explanation:
For the null hypothesis,
H0 : p = 0.63
For the alternative hypothesis,
Ha : p < 0.63
This is a left tailed test
Considering the population proportion, probability of success, p = 0.63
q = probability of failure = 1 - p
q = 1 - 0.63 = 0.37
Considering the sample,
Sample proportion, P = x/n
Where
x = number of success = 478
n = number of samples = 800
P = 478/800 = 0.6
We would determine the test statistic which is the z score
z = (P - p)/√pq/n
z = (0.6 - 0.63)/√(0.63 × 0.37)/800 = - 1.76
From the normal distribution table, the area below the test z score in the left tail 0.039
Thus
p = 0.039
Answer:
C
Step-by-step explanation:
Dot plot is usually in the form of stem & leaf. The only difference is that, stem& leaf presents the actual values while dot plot usually represent the value in dots. Hence, we can easily generate dot plot from stem & leaf!
For (a) dot plot and box plot, dot plot presents all the data while box plot presents only the five-num statistics, namely:
1. minimum
2. 1st quartile (Q1)
3. median
4. 3rd quartile (Q3)
5. Maximum
And outliers, if any!
Thus, dot plot cannot directly generate box plot
For (b). Histogram and stem & leaf. Although both usually help us understand the skewness of data distribution, however, histogram deals with frequency distribution (counts of number of occurrence) and plotted on the intervals and stem&leaf list the values.
For (d). Even though dot plot shoots up and down like the histogram, the content is different. In dot plot, it is the actual value represented in dots. But in histogram, it is the frequency distribution of the class intervals.
