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horrorfan [7]
2 years ago
13

On this map, Oxford Street is perpendicular to_______ , and Rosewood Street is perpendicular to ________. Assume that the street

intersections form right angles.

Mathematics
1 answer:
melamori03 [73]2 years ago
6 0
Hi there!

We are looking for perpendicular angles, which means the angle between the streets is 90 degrees. So, each time we need to find the street that intersects the given street with a 90 degree angle.

On this map, Oxford Street is perpendicular to Waterloo St., and Rosewood Street is perpendicular to Oak St..

The answers are (in correct order): Waterloo St. and Oak St..
~ Hope this helps you!
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Leni [432]
1=28:40 I don't know about the rest
4 0
2 years ago
Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10
Vladimir [108]

Answer:

0011100000

1010010001

0111001110

Step-by-step explanation:

As the question is not complete, Here is the complete question.

Suppose that the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Express each of these sets with bit strings where the ith bit in the string is 1 if i is in the set and 0 otherwise.

a) {3, 4, 5}

b) {1, 3, 6, 10}

c) {2, 3, 4, 7, 8, 9}.

So, we need to express a) b) and c) into bit strings.

Firstly, number of elements in the universal set represent the number of bits in the bit string.

Secondly, 1 = yes element is present in both universal set as well as in sub set.

0 = No, element is not present in sub set but present in universal set.

Hence, we have:

a) Sub set {3,4,5} = 0011100000  (As there are 3 1's which means only 3,4,5 are present in both universal set and subset.

Similarly,

b) Sub set {1, 3, 6, 10} = 1010010001

c) Sub set {2, 3, 4, 7, 8, 9} = 0111001110

5 0
2 years ago
A group of friends has gotten very competitive with their board game nights. They have found that overall, they each have won an
Amanda [17]

Answer: \mu_x=18\text{ hours}

\sigma_x=4\text{ hours}

Step-by-step explanation:

We know that mean and standard deviation of sampling distribution is given by :-

\mu_x=\mu

\sigma_x=\dfrac{\sigma}{\sqrt{n}}

, where \mu = population mean

\sigma =Population standard deviation.

n= sample size .

In the given situation, we have

\mu=18\text{ hours}

\sigma=6\text{ hours}

n= 2

Then, the expected mean and the standard deviation of the sampling distribution will be :_

\mu_x=\mu=18\text{ hours}

\sigma_x=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{2}}=4.24264068712\approx4  [Rounded to the nearest whole number]

Hence, the the expected mean and the standard deviation of the sampling distribution :

\mu_x=18\text{ hours}

\sigma_x=4\text{ hours}

7 0
2 years ago
Two students start a club the first week of school each member invites three new members the second week of school each of these
shtirl [24]

Answer:

26 people

Step-by-step explanation:

7 0
2 years ago
You are a school photographer taking individual and class pictures for 2 classes of 21 students each. On average, each individua
kramer
146 minutes in total. One student =3 minutes. So then 42x3= 126. Class picture is 10x2=20. So then add both of them you get 146.
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2 years ago
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