<u>Answer:</u>
Tabitha will use 12 teaspoons.
<u>Explanation: </u>
According to the question, Tabitha has a largest volume-measuring tool teaspoon, and she wants to use one-fourth cup of broth.
Given that 1 cup consists of 16 tablespoons and 1 tablespoon has 3 teaspoons.
From the data, we can calculate that;
16 tablespoons will be equal to (3*16) = 48 teaspoons.
Therefore, 1 cup = 48 teaspoons.
Substituting the data and we can calculate that 1/4 cup = 48/4 = 12 teaspoons.
Answer:
The value of the parameter is λ is 0.03553357
Step-by-step explanation:
Consider the provided function.
for −∞ < x < ∞.
It is given that standard deviation is given as 39.8 km.
Now we need to calculate the value of parameter λ.
The general formula for the probability density function of the double exponential distribution is: 
Where μ is the location parameter and β is the scale parameter.
Compare the provided equation with the above formula we get.
and μ = 0.
Standard deviation = √2β
Now substitute the value of β in .
Hence, the value of the parameter is λ is 0.03553357
Let's use J for James's age and A for Austin's age. The equations are:
J = A - 4
3J + A² = 28
Just plug (A - 4) in the place of J in the second equation. This gives you:
3(A - 4) + A² = 28
-->
A² + 3A - 12 = 28
-->
A² + 3A - 40 = 0
-->
(A - 5)(A + 8) = 0
-->
A = 5 or -8
-8 is nonsense, so Austin is 5 years old. Therefore, James is 1 year old.
(24, 12) and (36, 0). The least amount of flowering plants occurs when x=2y, and the largest amount occurs when y=0. These two points satisfy both conditions and both sum to 36.
Answer:
A and D
Step-by-step explanation:
Here, we shall be evaluating the validity of the statements;
A. Yes, A is true
There are four even numbers 2,4,6 and 8 and 4 odd number 1,3,5,7; The landing should be equal at 125 each
B. This is wrong
It is supposed to land half of the number of time s which is half of 250 and that is 125
C.This is wrong
The numbers greater than 4 are 5,6,7,8
Now, the probability should be 4/8 = 1/2 and that is 50%
D. This is correct
Number of times we have a landing on odd numbers is 250-135 = 115
The experimental probability of landing on an odd number is thus 115/250 = 0.46 which is 46%
