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AlexFokin [52]
2 years ago
13

Kaliska is jumping rope. The vertical height of the center of her rope off the ground R(t)R(t)R, left parenthesis, t, right pare

nthesis (in \text{cm}cmstart text, c, m, end text) as a function of time ttt (in seconds) can be modeled by a sinusoidal expression of the form a\cdot\cos(b\cdot t)+da⋅cos(b⋅t)+da, dot, cosine, left parenthesis, b, dot, t, right parenthesis, plus, d. At t=0t=0t, equals, 0, when she starts jumping, her rope is 0\text{ cm}0 cm0, start text, space, c, m, end text off the ground, which is the minimum. After \dfrac{\pi}{12} 12 π ​ start fraction, pi, divided by, 12, end fraction seconds, it reaches a height of 60\text{ cm}60 cm60, start text, space, c, m, end text from the ground, which is half of its maximum height

Mathematics
1 answer:
gizmo_the_mogwai [7]2 years ago
7 0

Answer:

Step-by-step explanation:

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Five data entry operators work at the data processing department of the Birmingham Bank. Each day for 30​ days, the number of de
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Answer:

Step-by-step explanation:

a)

  • p = Total Number of Defects / Sample Size x Number of Samples
  • 302 / 300 x 30 = 0.0336

  • z = Number of standard deviation = 3
  • σ = Standard deviation of sampling distribution
  • σ = p (1- p) / n = 0.0336 (1- 0.0336) / 300 = 0.0336 x 0.9664 / 300 = 0.0104

  • Here, n = number of observations in each sample

  • UCL = p+zσ = 0.0336 + 3(0.0104) = 0.0336 + 0.0312 = 0.0648 = 0.065

  • LCL = p-zσ = 0.0336 - 0.0312 = 0.0024 = 0.002

b) Hence, Lower control limit cannot be a negative number as percent defective cannot be a negative number. As such, No. Percent of defective records cannot be a negative number.

7 0
2 years ago
Esteban is reading a book with 16 pages. He has read 9 pages so far. How many pages does Esteban have left to read? Write two eq
Zielflug [23.3K]

Answer:

7 pages

Step-by-step explanation:

Given the total number of pages in the book are 16

The number of pages esteban already read are 9

Let the number of pages left out to read be x

Total number of pages = number of pages read + number of pages to be read

16=9+x

x=16-9

x=7 pages

Therefore There are 7 pages left out to be read.

8 0
1 year ago
Which graph shows the solution to the system of linear inequalities? x + 3y > 6 y ≥ 2x + 4 PLEASE HELP
Andrei [34K]

Answer:

x + 3y > 6

Step-by-step explanation:

Find two points that satisfy x + 3y = 6 and draw a DASHED line through them.

It is greater than so shade the section ABOVE that line.

Using the intercept method, the two points I chose are: (0, 2) & (6, 0)

y ≥ 2x + 4

Find two points that satisfy y = 2x + 4 and draw a SOLID line through them.

It is greater than so shade the section ABOVE that line.

The two points I chose are: (0, 4) & (1, 6)

The solution is where the shaded sections overlap.

3 0
1 year ago
Read 2 more answers
At one of New York’s traffic signals, if more than 17 cars are held up at the intersection, a traffic officer will intervene and
Alinara [238K]
Scenarios B, D, and F require a police officer. In scenario B, 1:00-2:00pm, and scenario F, 5:00-6:00pm, there are 24 cars. In scenario D, 3:00-4:00pm, there are 21 cars. Both 24 and 21 are greater than 17, so a traffic officer is needed. However, in other scenarios, the number of cars are all less than 17, and no officer is needed.
8 0
1 year ago
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The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20. Each d
Kruka [31]

Answer:

The probability that exactly 15 defective components are produced in a particular day is 0.0516

Step-by-step explanation:

Probability function : P(X=x)=e^{-\lambda} \frac{\lambda^x}{x!}

We are given that The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20.

So,\lambda = 20

we are supposed to find the probability that exactly 15 defective components are produced in a particular day

So,x = 15

Substitute the values in the formula :

P(X=15)=e^{-20} \frac{20^{15}}{15!}

P(X=15)=e^{-20} \frac{20^{15}}{15!}

P(X=15)=0.0516

Hence the probability that exactly 15 defective components are produced in a particular day is 0.0516

8 0
1 year ago
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