Kaliska is jumping rope. The vertical height of the center of her rope off the ground R(t)R(t)R, left parenthesis, t, right pare
nthesis (in \text{cm}cmstart text, c, m, end text) as a function of time ttt (in seconds) can be modeled by a sinusoidal expression of the form a\cdot\cos(b\cdot t)+da⋅cos(b⋅t)+da, dot, cosine, left parenthesis, b, dot, t, right parenthesis, plus, d. At t=0t=0t, equals, 0, when she starts jumping, her rope is 0\text{ cm}0 cm0, start text, space, c, m, end text off the ground, which is the minimum. After \dfrac{\pi}{12} 12 π start fraction, pi, divided by, 12, end fraction seconds, it reaches a height of 60\text{ cm}60 cm60, start text, space, c, m, end text from the ground, which is half of its maximum height
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Refer to the diagram shown below.
The exit for Freestone is built midway between Roseville and Edgewood,
therefore the distance from O to the new exit is
(1/2)*(33+55) = 44 mi.
Let x = distance from Midtown to the new exit.
Because the distance from O to the new exit is equal to (x + 17), therefore
x + 17 = 44
x = 44 - 17 = 27 mi.
Answer:
When the new exit is built, the distance from the exit for Midtown to the exit for Freestone will be 27 miles.
The exit for Freestone is built midway between Roseville and Edgewood,
therefore the distance from O to the new exit is
(1/2)*(33+55) = 44 mi.
Let x = distance from Midtown to the new exit.
Because the distance from O to the new exit is equal to (x + 17), therefore
x + 17 = 44
x = 44 - 17 = 27 mi.
Answer:
When the new exit is built, the distance from the exit for Midtown to the exit for Freestone will be 27 miles.