Answer:
<u>The rabbit could be at eight different numbers of the number line:</u>
<u>-7, - 5, - 3, - 1, 1, 3, 5, and 7.</u>
Step-by-step explanation:
Let's simulate each of the jumps of the rabbit in all the possible directions, as follows:
Option 1: - 4 - 2 - 1 = -7
Option 2: - 4 - 2 + 1 = -5
Option 3: - 4 + 2 - 1 = - 3
Option 4: - 4 + 2 + 1 = - 1
Option 5: 4 - 2 - 1 = 1
Option 6: 4 - 2 + 1 = 3
Option 7: 4 + 2 - 1 = 5
Option 8: 4 + 2 + 1 = 7
Answer:
option 4 (2,-15)
Step-by-step explanation:
If N is first and L is last, then we just need to find all of the permutations for M, O, and P
with first letter M: MOP MPO
with first letter O: OPM OMP
with first letter P: PMO POM
Now, place the N in front and the L at the end of each permutation. There are 6 permutations in total:
NMOPL NMPOL
NOPML NOMPL
NPMOL NPOML
Conveniently, your number line has 8 divisions in each unit interval, so finding 5/8 is a matter of counting 5 divisions.
The additive inverse of a number has the opposite sign from the number, so m = -5/8. The sum of a number and its additive inverse is zero. (That is the definition of additive inverse.)