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2 years ago

HELP PLEASE !!!

Mathematics

1 answer:

trasher [3.6K]2 years ago

6 0

Answer:

............................................

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Below are summary statistics for the sizes (in acres) of some local vineyards. Using the summary statistics, complete parts (a)

rjkz [21]

Answer:

option B

Step-by-step explanation:

The symmetric distribution have close or approximate values of median and mean. In the given scenario mean is 48.5 and median is 33. We can see that the both values significantly differs. Also, given mean is greater than median(48.5>33) . Thus, the distribution is positively skewed and not symmetrical.

Hence, the distribution is skewed because mean and median significantly differ from each other.

3 0

2 years ago

An employee at a clothing store makes a base salary of $2,800 a month plus 6.75% of the sales that they make. The function E(s)=

Gennadij [26K]

Answer:

3,340$

Step-by-step explanation:

e(8000)=.0675(8000)+2800

e(8000)=540+2800

e(8000)=3340

4 0

2 years ago

Find an explicit rule for the nth term of the sequence. -5, -25, -125, -625, ...

Keith_Richards [23]

An=a1(r)^(n-1)
a1=first erm
r=common ratio

firs term is -5
we times each term by 5 to get next term so r=5

$a_n=-5(5)^{n-1}$ is the explicit formula

8 0

2 years ago

ΔABC is dilated using a scale factor of 12 to produce ΔA'B'C'. Select all of the statements that apply to the transformation.

GalinKa [24]

Answer:

Options (3) and (6)

Step-by-step explanation:

ΔABC is a dilated using a scale factor of $\frac{1}{2}$ to produce image triangle ΔA'B'C'.

Since, dilation is a rigid transformation,

Angles of both the triangles will be unchanged or congruent.

m∠A = m∠A' and m∠B = m∠B'

Since, sides of ΔA'B'C' = $\frac{1}{2}$ of the sides of ΔABC

Area of ΔA'B'C' = $\frac{1}{2}(\text{Area of triangle ABC})$

Area of ΔABC > Area of ΔA'B'C'

Since, angles of ΔABC and ΔA'B'C' are congruent, both the triangles will be similar.

ΔABC ~ ΔA'B'C'

Therefore, Option (3) and Option (6) are the correct options.

3 0

1 year ago

The owner of a manufacturing plant employs eighty people. As part of their personnel file, she asked each one to record to the n

wariber [46]

Answer:

Mean of the sample = 27.83

The variance of the the sample = 106.96

Standard deviation of the sample = 10.34

Step-by-step explanation:

Step(i):-

Given random sample of six employees

x 26 32 29 16 45 19

mean of the sample

$x^{-} = \frac{26+32+29+16+45+19}{6} = 27.83$

Mean of the given data = 27.83

Step(ii):-

Given data

x : 26 32 29 16 45 19

x - x⁻ : -1.83 4.17 1.17 -11.83 17.17 -8.83

(x - x⁻)² : 3.3489 17.3889 1.3689 139.9489 294.80 77.9689

∑ (x-x⁻)² = 534.8245

Given sample size 'n' =6

The variance of given data

S² = ∑(x-x⁻)² / n-1

$S^{2} = \frac{534.8245}{6-1} = 106.9649$

The variance of the given sample = 106.9649

Step(iii):-

Standard deviation of the given data

$S = \sqrt{variance} = \sqrt{106.9649} =10.3423$

Standard deviation of the sample = 10.3423

8 0

2 years ago