Question

Two old rsm students were standing twenty feet apart when they spotted mrs. rifkin. if they immediately run in opposite directions with speeds of 180 feet per minute and 120 feet per minute respectively, how many minutes will pass before they are 2,420 feet apart?

Answer 1

8 minutes  would pass before they are 2,420 feet part

• Let x represent the speed of the first student, X = $180ft/min$
• And Y represent the speed of the second student, Y = $120ft/min$
• The distance between the two students = $2,420$ – $20$ = $2400$

Further Explanation

Since the two students are moving in the opposite direction, then the relative speed will be the sum of their speed. This can be expressed as:

Relative speed = speed of student X + the speed of student Y

Relative speed = $120$ + $180$  

= $300ft/min$

Recall the distance between the two students is $2,400$  ,

To determine the time that would pass before they are 2,420 feet apart, then we have to use the formula to calculate time, which is:

Time = distance / time

= $\frac{2400}{300}$

=  $8minutes$

Thus, 8 minutes  would pass before they are 2,420 feet part.

LEARN MORE:

• If they immediately ran in opposite directions with speeds of 180 feet per minute brainly.com/question/10378018
• Two RSM students are standing 20ft apart and spot Mrs. Rifkin brainly.com/question/13074188

KEYWORDS:

• distance
• speed
• time
• 120 feet per minutes
• 180 feet per minutes

Answer 2

Speed of student A is 180 ft/min
Speed of student B is 120 ft/min
Relative speed=(120+180)=300 ft/min
Distance between them is 2420 ft
Time taken for them to meet will be:
time=distance/speed
=(2420-20)/300
=8 min