(5.75,0)
Let A be (x1,y1) , B be (x2,y2) , P be (x,y) and the ratio be m:n
Formula is,
x=(x2*m+x1*n)/(m+n)
y=(y2*m+y1*n)/(m+n)
Fractions are the part/whole. We can set this up to be...
3/5 = 756
756 x5/3 = 1260.
if she had 1260 to begin with and spent 756, she would have 504.00 left.
Answer: high test-retest reliability
Step-by-step explanation: this is because the result of the survey was thesame with the previous result, despite the space of time between when the first survey was conducted and when the second survey was conducted. There was know observable difference in result and if conducted in the next 3 months again, it will give same result, this strongly indicate that the survey has high test-retest reliability.
Answer:

Step-by-step explanation:






Let , side lawn is a.
Area of boundary is :

Now, total cost is given by :

Area left is :

Price to empty space with turfs is :

Therefore, the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre is Rs 262500.
Hence, this is the required solution.