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Kazeer [188]
2 years ago
6

1) The cost of constructing a path 5 m broad inside the boundary of a square lawn at Rs 36.25 per sq. metre is Rs 90625. What is

the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre?​
Mathematics
1 answer:
Svetach [21]2 years ago
3 0

Let , side lawn is a.

Area of boundary is :

A=4\times5\times a\\\\A=20a\ m^2

Now, total cost is given by :

T=20a\times 36.25\\\\90625=725a\\\\a=125\ m

Area left is :

A'=a^2-20a\\\\A'=125^2-20\times 125\ m^2\\\\A'=13125\ m^2

Price to empty space with turfs is :

P=A'\times 20\\\\P=13125\times 20\\\\P=262500

Therefore, the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre is Rs 262500.

Hence, this is the required solution.

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The Foot Locker is having a 60% off sale on shorts. John paid $18 for a pair of shorts. What was the original price of the short
AURORKA [14]

Answer:

$30 is the price of the original pair of sneakers.

Step-by-step explanation:

You wanna cross multiply so you put :

18. 60

_ = _

x. 100

You multiply 18 the cost of the sneakers by 100 and then divide the product (1800) by 60 and you get $30.

MARK ME AS BRAINLIEST!

6 0
1 year ago
LeAnn is purchasing giftwrap for a box that measures 8 inches long, 6 inches wide, and 6 inches tall. Calculate the total area o
Pavel [41]

Let

L---------> the length side of the box

W--------> the width side of the box

H-------> the height of the box

we know that

L=8\ in\\W=6\ in\\H=6\ in

the surface area of the box is equal to

S=2*area\ of\ the\ base+perimeter\ of\ the\ base*H

<u>Find the area of the base</u>

A=L*W=8*6=48\ in^{2}

<u>Find the perimeter of the base</u>

P=2*L+2*W=2*8+2*6=28\ in

<u>Find the surface area</u>

S=2*48+28*6

S=264\ in^{2}

therefore

<u>the answer is</u>

the total area of the box that will be covered in gift wrap is 264\ in^{2}

8 0
2 years ago
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Yasmin bought several items at the discount store. She paid 8.75 percent sales tax, an amount of $4.59, on the total amount of h
sveticcg [70]

divide the total tax by the rate

8.75% = 0.0875

4.59/.0875 = 52.457 round to 52.46

6 0
2 years ago
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Mr. Barrow scored his high school students' essays on a scale of 0 to 10. He recorded data about the scores in the table below.
Fynjy0 [20]

09 08 07 06 10  1

wrryetryytrwertry (It was too short)

7 0
1 year ago
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Part A: During what interval(s) of the domain is the water balloon's height increasing? (2 points) Part B: During what interval(
Allushta [10]

Answer:

A). interval 0 ≤ x ≤ 2

B). interval 2 ≤ x ≤ 4

C). interval 8 ≤ x ≤ 10

D). h(14) = 0

Step-by-step explanation:

Part A.

In the interval 0 ≤ x ≤ 2, height of the water balloon is increasing.

Part B.

In the interval 2 ≤ x ≤ 4, height of the water balloon is constant.

Part C.

In the interval 8 ≤ x ≤ 10, height of the water balloon is decreasing the fastest.

Slope of the line between x = 8 and x = 10 is the maximum.

Part D.

Since at x = 10 height of the water balloon is h = 0, therefore, at any moment after x = 10 seconds height of the balloon will remain zero.

7 0
2 years ago
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