Answer:
The standard deviation of that data set is 3.8
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 55
95% of the data fall between 47.4 and 62.6. This means that 47.4 is 2 standard deviations below the mean and 62.6 is two standard deviations above the mean.
Using one of these points.
55 + 2sd = 62.6
2sd = 7.6
sd = 7.6/2
sd = 3.8
The standard deviation of that data set is 3.8
There is multiple ways but one of them is 3 SUV and 1 car and that will give him $315.
I hope this helps :)
Answer:
1/9; 4/9; 1/12; 1/6
Step-by-step explanation:
the probability that both numbers are greater than 6 if the same number can be chosen twice--> 3/9 * 3/9 = 1/9
the probability that both numbers are less than 7 if the same number can be chosen twice --> 6/9 * 6/9 = 4/9
the probability that both numbers are odd numbers less than 6 if the same numbers cannot be chosen twice --> 3/9 * 2/8 = 1/12
the probability that both numbers are even numbers if the same numbers cannot be chosen twice --> 4/9 * 3/8 = 1/6
Answer:
a. is not found to be significant.
Step-by-step explanation:
Regression analysis is a statistical technique which is used for forecasting. It determines the relationship between two variables. It determines the relationship of two or more dependent and independent variables. It is widely used in stats to find trend in the data. It helps to predict the values of dependent and independent variables. In the given question, there are 25 observations and the regression equation is given. X and Y are considered as dependent variables.
The answer is C. The numerator 7x+14 can be factored as 7(x+2). The denominator 2x^2+2x-6 can be factored as (x+2)(2x-3). The greatest common divisor of 7(x+2) and (x+2)(2x-3) is obviously x+2, which is contained in both of the two expressions.
