As the problem states, to solve this, we are going to use the equation

where

is the loudness in dB

is the intensity of a sound

<span>is the minimum intensity detectable by the human ear
</span>
We know for our problem that

; we also now that the minimum intensity detectable by the human ear is

, so

. Lets replace those values in our equation to find

:


Qe can conclude that since the explosion is under 100dB, it does not violates the regulation of the town. We used tow physical values to calculate the answer: the intensity of the sound of the explosion,

, and the minimum intensity detectable by the human ear

.
Answer:
%=-7t
solution -7% per 1:00
Step-by-step explanation:
Hope this helps
A. 2x3=6 and 6x12=72 so 78 is greater than 36
6+72=79 which is less than 90
Answer:
76 *5 = 380 $
184 - 76 = 108
108 * 4 = 432
432 + 380 = 812
Step-by-step explanation:
Answer:
The correct option is 1. The atmospheric pressure is 8 g/mm² at sea level.
Step-by-step explanation:
In the given graph y-axis represents the atmospheric pressure, in grams per square millimeter, and x-axis represents the altitude in miles above sea level.
The y-intercept of the graph is 8. It means the atmospheric pressure is 8 g/mm² when the altitude above sea level is 0.
Therefore atmospheric pressure is 8 g/mm² at sea level and option 1 is correct.
The graph represents a decreasing function.
As the altitude in miles above sea level increases the atmospheric pressure decreases and vice versa.
As the altitude in miles above sea level increases without bound the atmospheric pressure approaches 0 g/mm².
Therefore options 2,3 and 4 are incorrect.