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1 year ago

The table shows the price of admission at eight theaters.

Mathematics

2 answers:

Nostrana [21]1 year ago

3 0

The answer would have to be 11.00 if im correct.

PilotLPTM [1.2K]1 year ago

3 0

Answer: The mean absolute deviation of the data set is <u>8.8125</u>

Step-by-step explanation:

First find the mean of the data by adding all data points together then divide by the number of data points. 5.00+7.50+8.25+8.00+9.75+10.25+11.00+10.75=70.5

70.5÷8=8.8125

Secondly, find the absolute value of the mean. In short, the absolute value of any number is the same number but positive.

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Consider the table representing a rational function. Which equation could represent a vertical asymptote of the graph of the fun

AleksAgata [21]

Answer:

Step-by-step explanation:

According to the given table, we see that for <em>x = -1</em>, the function is not defined, that means that the rational function has a restriction there, and such restriction is shown as an asymptote in the graph of the function.

So, basically, we could say that the given rational function has one asymptote and it's at x = -1, which is a vertical asymptote, because all forms like x = k, are vertical lines, that is, they are parallel to the vertical axis.

Therefore, the right answer is the third choice.

7 0

2 years ago

Read 2 more answers

Given f(x)=x^2+12x+26 .

lapo4ka [179]

f(x)=x^2+12x+26

Vertex form of f(x) = a(x-h)^2 +k

We change f(x) into vertex form using completing the square method

$f(x)=x^2+12x+26$

We take half of square of middle term

middle term is 12

Half of square of 12 is $\frac{12}{2}=6$ then 6^2 = 36

Add and subtract 36 to complete the square

$f(x)=(x^2+12x+36)+26-36$

$f(x)= (x+6)^2 +26 - 36 f(x)= (x+6)^2 -10$

The vertex form $f(x)= (x+6)^2 -10$

6 0

1 year ago

What number must we multiply by $-\frac23$ to get a product of $\frac34$?

stich3 [128]

Let x be unknown number. If number x is multiplied by $-\dfrac{2}{3}$ and the product is equal to $\dfrac{3}{4},$ then

$x\cdot \left(-\dfrac{2}{3}\right)=\dfrac{3}{4}.$

To find x you should divide $\dfrac{3}{4}$ by $-\dfrac{2}{3}:$

$x=\dfrac{\dfrac{3}{4}}{-\dfrac{2}{3}}=\dfrac{3}{4}\cdot \left(-\dfrac{3}{2}\right)=-\dfrac{3\cdot 3}{4\cdot 2}=-\dfrac{9}{8}.$

Answer: $x=-\dfrac{9}{8}$

7 0

2 years ago

What is 15 tens - 1 gross

vampirchik [111]

Answer:

see the explanation

Step-by-step explanation:

we know that

A gross is equal to 120 ones or ten dozen

what is 15 tens - 1 gross

we know that

15 tens means ----> That you are adding 10, 15 times or multiplying 10 by 15, which gives you

$10(15)=150$

1 gross means ---> That you are adding 10, 12 times or multiplying 10 by 12

which gives you

$10(12)=120$

The algebraic expression of 15 tens - 1 gross is equal to

$150-120=30$

Convert to word expression

3 tens

8 0

1 year ago

The aquarium at Sea Critters Depot contains 140 fish. Eighty of these fish are green swordtails (44 female and 36 male) and 60 a

maxonik [38]

Given that:

Total number of fish = 140

Fish are green swordtails female = 44

Fish are green swordtails male = 36

Fish are orange swordtails female = 36

Fish are orange swordtails male = 24

Solution:

A. We have to find the probability that the selected fish is a green swordtail.

$\text{P(green swordtail)}=\dfrac{\text{Total green swordtail fish}}{\text{Total fish}}$

$\text{P(green swordtail)}=\dfrac{80}{140}$

$\text{P(green swordtail)}=\dfrac{4}{7}$

Therefore, the probability that the selected fish is a green swordtail is $\dfrac{4}{7}.$

B. We have to find the probability that the selected fish is male.

$\text{P(Male fish)}=\dfrac{\text{Total male fish}}{\text{Total fish}}$

$\text{P(Male fish)}=\dfrac{36+24}{140}$

$\text{P(Male fish)}=\dfrac{60}{140}$

$\text{P(Male fish)}=\dfrac{3}{7}$

Therefore, the probability that the selected fish is a male, is $\dfrac{3}{7}.$

C. We have to find the probability that the selected fish is a male green swordtail.

$\text{P(Male green swordtail)}=\dfrac{\text{Total male green swordtail fish}}{\text{Total fish}}$

$\text{P(Male green swordtail)}=\dfrac{36}{140}$

$\text{P(Male green swordtail)}=\dfrac{9}{35}$

Therefore, probability that the selected fish is a male green swordtail is $\dfrac{9}{35}.$

We have to find the probability that the selected fish is either a male or a green swordtail.

$\text{P(Male or green swordtail)}=\dfrac{\text{Total male or green swordtail fish}}{\text{Total fish}}$

$\text{P(Male or green swordtail)}=\dfrac{44+36+24}{140}$

$\text{P(Male or green swordtail)}=\dfrac{96}{140}$

$\text{P(Male or green swordtail)}=\dfrac{24}{35}$

Therefore, the probability the selected fish is either a male or a green swordtail is $\dfrac{24}{35}.$

4 0

1 year ago