![\sqrt[7]{(7x^3y^2)^{2} } = \sqrt[7]{(49x^6y^4)}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B%287x%5E3y%5E2%29%5E%7B2%7D%20%7D%20%3D%20%5Csqrt%5B7%5D%7B%2849x%5E6y%5E4%29%7D%20)
In a fractional exponent the denominator tells what root it is (7th root in this case) and the numerator tells what the value in the parenthesis is raised to (2nd power in this case)
Thats good for Alex?
Haha, what is the rest of the question? I am happy to help
Answer:
$122.89
Step-by-step explanation:
The two number you have in this equation are 108.75 and 13% (or .13)
first you want to multiply 108.75 to .13
108.75 * .13 = 14.1375
Now, you add 14.1375 to 180.75 and round to the nearest hundredth
180.75+ 14.1375=122.8875
$122.89
Answer:
69.3 mi
Step-by-step explanation:
Let x represent the distance of the ship from its original position.
x²= 40² + 35² -2(40)(35)cos(135)
x= 69.3 mi
Answer:
The probability that the next failure will not occur before 30 months have elapsed is 0.0454
Step-by-step explanation:
Using Poisson distribution where
t= number of units of time
x= number of occurrences in t units of time
λ= average number of occurrences per unit of time
P(x;λt) = e raise to power (-λt) multiplied by λtˣ divided by x!
here λt = 25
x= 30
P(x= 30) = 25³⁰e⁻²⁵/ 30!
P (x= 30) = 8.67 E41 * 1.3887 E-11/30! (where E= exponent)
P (x=30) = 1.204 E31/30!
Solving it with a statistical calculator would give
P (x=30) = 0.0454
The probability that the next failure will not occur before 30 months have elapsed is 0.0454
