Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
Original equation is 
So,
and

If we compare this equation with the given options, we can easily find that this matches with the last one
with P = p/2.
Hence, correct option is
.
Answer: See explanation
Step-by-step explanation:
Based on the scenario in the question, the expression to calculate the number of boxes of sugar Alonso can buys will be:
= 2.75 + 11.50S ≤ 55
When solved further, this will be:
2.75 + 11.50S ≤ 55
11.50S ≤ 55 - 2.75
11.50S ≤ 52.25
S ≤ 52.25 / 11.50
S ≤ 4.54
He can buy 4 boxes of sugar
Answer:
12
Step-by-step explanation:
Well, 12/12=1, which I guess is the smallest number we can get, and 12 is divisible by 2 too.