Answer:
The value that is greater than 45% of the data values is approximately 137.84.
Step-by-step explanation:
The key is transforming values from this distribution to a z-score range and finding the corresponding value using a z-score table.
We are looking for a value x which attains a critical z-score that corresponds to the (100-45)%=55-th percentile:

The critical z value (from z-score table, online) is: -0.12, so:

The value that is greater than 45% of the data values is approximately 137.84.
Answer:
0.0013
Step-by-step explanation:
To do this, we need to use a normal distribution table with Z score values, like the one I'm attaching here.
Now, the expression to calculate the Z value is the following:
Z = x - μ / (σ/√n)
Where:
μ: mean
σ: standard deviation
x: value required
n: sample population
Now that we have the data, let's calculate the Z value:
Z = 66,000 - 60,000 / (4000/√4)
Z = 3
Now, let's look at the table to get the value that belongs to this Z score. According to the table, it's 0.0013
Therefore, the likelihood would be 0.0013
Answer:
The Answer is -16
Step-by-step explanation:
The equation to this would be -352 / 22, which would give you 16, hope this helped!
Answer:
2.13
Step-by-step explanation:
because 2.1349 is closer to 2.13 than 2.14 because the number 4 is less than 5 so it's closer to 0