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Anton [14]
1 year ago
11

3. Standard deviation is ________. a mean of squared differences the square root of the variance unit-free the covariance 4. Sta

ndard deviation is useful because it ________. provides a measure of deviation from the median has no units and can therefore apply to all data ignores outliers has the same units as the underlying data
Mathematics
1 answer:
Ksenya-84 [330]1 year ago
5 0

Answer:

3. Standard deviation is the square root of the variance.

4. Standard deviation is useful because it has the same units as the underlying data.

Step-by-step explanation:

3. In statistics, the dispersion in a given data with respect to its mean distribution can be determined or measured by standard deviation and variance. The standard deviation of a distribution can also be determined as the square root of variance.

4. Standard deviation is measured in the same units as that of the original data. Thus it has the same units as the underlying data.

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A container holds 2,000 g of water. This is the same as:
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The simplest form of the expression -2x2(x – 5) + x(2x2 – 10x) + x is ____________<br> .
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x

Step-by-step explanation:

Given

- 2x²(x - 5) + x(2x² - 10x) + x ← distribute both parenthesis

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2 years ago
7: Maribel blinks her eyes 105 times in 5 minutes. If b represents the number of times Maribel blinks in m minutes, what is a li
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Step-by-step explanation:

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2 years ago
A box contains 5 red and 5 blue marbles. Two marbles are withdrawn randomly. If they are the same color, then you win $1.10; if
topjm [15]

Answer:

a) The expected value is \frac{-1}{15}

b) The variance is  \frac{49}{45}

Step-by-step explanation:

We can assume that both marbles are withdrawn at the same time. We will define the probability as follows

#events of interest/total number of events.

We have 10 marbles in total. The number of different ways in which we can withdrawn 2 marbles out of 10 is \binom{10}{2}.

Consider the case in which we choose two of the same color. That is, out of 5, we pick 2. The different ways of choosing 2 out of 5 is \binom{5}{2}. Since we have 2 colors, we can either choose 2 of them blue or 2 of the red, so the total number of ways of choosing is just the double.

Consider the case in which we choose one of each color. Then, out of 5 we pick 1. So, the total number of ways in which we pick 1 of each color is \binom{5}{1}\cdot \binom{5}{1}. So, we define the following probabilities.

Probability of winning: \frac{2\binom{5}{2}}{\binom{10}{2}}= \frac{4}{9}

Probability of losing \frac{(\binom{5}{1})^2}{\binom{10}{2}}\frac{5}{9}

Let X be the expected value of the amount you can win. Then,

E(X) = 1.10*probability of winning - 1 probability of losing =1.10\cdot  \frac{4}{9}-\frac{5}{9}=\frac{-1}{15}

Consider the expected value of the square of the amount you can win, Then

E(X^2) = (1.10^2)*probability of winning + probability of losing =1.10^2\cdot  \frac{4}{9}+\frac{5}{9}=\frac{82}{75}

We will use the following formula

Var(X) = E(X^2)-E(X)^2

Thus

Var(X) = \frac{82}{75}-(\frac{-1}{15})^2 = \frac{49}{45}

7 0
2 years ago
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