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luda_lava [24]
2 years ago
5

The polynomial function f (x) = 5 x Superscript 5 Baseline + sixteen-fifths x minus 3 is graphed below. On a coordinate plane, p

oint P is shown on the graph of a function. Point P is at (0.6, 0). Which is a potential rational root of f(x) at point P?
Mathematics
2 answers:
Goryan [66]2 years ago
6 0

NSWER

The root at point P may be 3/5

EXPLANATION

The given function is

f(x)=5x^{5}+\frac{16}{5} x-3

The potential rational roots are all factors of -3 expressed over all factors of 5.

These are:

±\frac{1}{5} , ±\frac{3}{5}

Since the root of f(x) at P is closer to 1 that zero and it is positive , that potential may be \frac{3}{5}

olya-2409 [2.1K]2 years ago
4 0

Answer:

3/5

Step-by-step explanation:

What divisor is represented by the synthetic division below? x + 5. One factor of  x^3+x^2+x+1. If f(-5) = 0, what are all the factors of the function mc022-... -4 and 3. The polynomial function f(x) = 5x5 + 3x - 3 is graphed below. The root at point P maybe 3/5  3.

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A coordinate grid with 2 lines. The first line is labeled y equals 0.5 x plus 3.5 and passes through (negative 3, 1), (negative
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d

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Marginal cost At a certain factory the marginal cost is 3(q-4)^2 dollars per unit when the level of production is q units.
viktelen [127]

Answer:

a.) C(q) =  -(1/4)*q^3 +  3q^2  -  12q + OH          b.) $170

Step-by-step explanation:

(a) Marginal cost is defined as the decrease or increase in total production cost if output is increased by one more unit. Mathematically:

Marginal cost (MC) = change in total cost/change in quantity

Therefore, to derive the equation for total production cost, we need to integrate the equation of marginal cost with respect to quantity. Thus:

Total cost (C) = Integral [3(q-4)^2] dq = -(1/4)*(q-4)^3 + k

where k is a constant.

The overhead (OH) = C(0) = -(1/4)*(0-4)^3 + k = -16 + k

C(q) = -(1/4)*(q^3  - 12q^2  + 48q - 64) + k = -(1/4)*q^3 +  3q^2  -  12q  -16 + k

Thus:

C(q) =  -(1/4)*q^3 +  3q^2  -  12q + OH

(b) C(14) = -(1/4)*14^3 +  3*14^2  -  12*14 + 436 = -686 + 588 - 168 + 436 = $170

7 0
2 years ago
in a certain class, 22 pupils take one or more of chemistry, economic, government. 12 take economic (E), 8 take government (G) a
mash [69]

Answer:

ai) n(E⋂C) = ∅ = null

n(E⋂G) = 4

aii) see attachment

bi) n(C⋂G) = x = 1

bii) n(G) only = 3

Step-by-step explanation:

Let chemistry = C

Economic = E

Government = G

n(E) = 12

n(G) = 8

n(C) = 7

ai) number of pupils for economics and chemistry = 0

number of pupils for economics and government = 4

The set notation for both:

n(E⋂C) = ∅ = null

n(E⋂G) = 4

aii) find attached the Venn diagram

bi) n(C⋂G) = ?

Let number of n(C⋂G) = x

From the Venn diagram

n(C) only = 12-4 = 8

n(G) only = 8-(4+x) = 4-x

n(E) only = 7-x

n(E⋂C⋂G) = 0

n(E⋂C) = 0

n(E⋂G) = 4

Total: 8+ 4-x + 7-x + x + 0+0+4 = 22

23 -x = 22

23-22 = x

x = 1

n(C⋂G) = x = 1

Number of pupils that take both chemistry and government = 1

(bii) government only = n(G) only = 4-x

n(G) only = 4-1 = 3

Number of students that take government only = 3

8 0
2 years ago
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Mamont248 [21]
In order to find the percent error, we need to first find the difference between what was expected and what is actually costed. We do this by subtracting:

525-462=63

So now we know that the expected amount was off by $63. To find the percent error, we need to take this $63, and divide it by the amount that was estimated. Let's do that now:

\frac{63}{462}=0.1364

However this is in decimal form. We need to multiply by 100 in order to get it in a percent:

0.1364*100=13.64%

Now we know that the percent error of the hospital bill estimate is 13.64%.
6 0
2 years ago
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