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Kamila [148]
2 years ago
9

The Naturally Made Bath and Body store pays $550 a month for rent and utilities. The average cost for its products to be manufac

tured is about $3.00 an item. If the average price for a product sold in the store is $5.50, what will the break-even point be? Let x represent the number of products sold. The break-even point occurs when the cost function equals the revenue function. 550 + 3.00x = 5.50x Naturally Made needs to sell products to break even. The cost or revenue when it sells the break-even number of products will be $
Mathematics
2 answers:
andreyandreev [35.5K]2 years ago
8 0
You need 220 products
Lilit [14]2 years ago
6 0

Answer:

220 products need to be sold to break it even.

Step-by-step explanation:

550 + 3.00x = 5.50x

550 = 2.50x

220 = x

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Which products result in a difference of squares? Select three options. A. (x minus y)(y minus x) B. (6 minus y)(6 minus y) C. (
solniwko [45]

Answer:

Step-by-step explanation:

Hello, please consider the following.

A. (x minus y)(y minus x)

  (x-y)(y-x)=-(x-y)(x-y)=-(x-y)^2

   This is not a difference of squares.

B. (6 minus y)(6 minus y)

   (6-y)(6-y)=(6-y)^2

   This is not a difference of squares.

C. (3 + x z)(negative 3 + x z)

   This is a difference of squares.

   \boxed{(3+xz)(-3+xz)=(xz+3)(xz-3)=(xz)^2-3^2}

D. (y squared minus x y)(y squared + x y)

   This is a difference of squares.

   \boxed{(y^2-xy)(y^2+xy)=(y^2)^2-(xy)^2}

E. (64 y squared + x squared)(negative x squared + 64 y squared)

   This is a difference of squares.

   \boxed{(64y^2+x^2)(-x^2+64y^2)=(64y^2+x^2)(64y^2-x^2)=(64y^2)^2-(x^2)^2}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0
2 years ago
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A group of eight grade 11 and five grade 12 students wish to be on the senior prom committee. The committee will consist of thre
BaLLatris [955]
5/13*4/12*3/11=5/143 I believe
7 0
2 years ago
500 grams of tomatoes cost £1.76 how much will 1.75kg cost??
ValentinkaMS [17]
500 grams equals 0.50 kg so multiply 1.76 3 times to get 5.28, then divide 1.76 by 2 to get .88 add the two together to get 6.16
3 0
2 years ago
Use Simpson's Rule with n = 10 to estimate the arc length of the curve. Compare your answer with the value of the integral produ
SOVA2 [1]

y=\ln(6+x^3)\implies y'=\dfrac{3x^2}{6+x^3}

The arc length of the curve is

\displaystyle\int_0^5\sqrt{1+\frac{9x^4}{(6+x^3)^2}}\,\mathrm dx

which has a value of about 5.99086.

Let f(x)=\sqrt{1+\frac{9x^4}{(6+x^3)^2}}. Split up the interval of integration into 10 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], ..., [9/2, 5]

The left and right endpoints are given respectively by the sequences,

\ell_i=\dfrac{i-1}2

r_i=\dfrac i2

with 1\le i\le10.

These subintervals have midpoints given by

m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4

Over each subinterval, we approximate f(x) with the quadratic polynomial

p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}

so that the integral we want to find can be estimated as

\displaystyle\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx

It turns out that

\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{f(\ell_i)+4f(m_i)+f(r_i)}6

so that the arc length is approximately

\displaystyle\sum_{i=1}^{10}\frac{f(\ell_i)+4f(m_i)+f(r_i)}6\approx5.99086

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2 years ago
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Hi there!

~

R = \frac{2.1}{sin 67.5}

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(A)

Hope this helped you!

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2 years ago
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