Answer:
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
Step-by-step explanation:
From the given triangle JKL;
Hypotenuse KJ = 10.9
Length LJ is the opposite = 8.9cm
The angle LKJ is the angle opposite to side KJ = x
Using the SOH CAH TOA Identity;
sin theta = opp/hyp
sin LKJ = LJ/KJ
Sinx = 8.9/10.9
x = arcsin(8.9/10.9)
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
Answer: The value of x in trapezoid ABCD is 15
Step-by-step explanation: The trapezoid as described in the question has two bases which are AB and DC and these are parallel. Also it has sides AD and BC described as congruent (that is, equal in length or measurement). These descriptions makes trapezoid ABCD an isosceles trapezoid.
One of the properties of an isosceles trapezoid is that the angles on either side of the two bases are equal. Since line AD is equal to line BC, then angle D is equal to angle C. It also implies that angle A is equal to angle B.
With that bit of information we can conclude that the angles in the trapezoid are identified as 3x, 3x, 9x and 9x.
Also the sum of angles in a quadrilateral equals 360. We can now express this as follows;
3x + 3x + 9x + 9x = 360
24x = 360
Divide both sides of the equation by 24
x = 15
Therefore, in trapezoid ABCD
x = 15
Below are the choices that can be found from other sources:
A. 42
<span>B. 45 </span>
<span>C. 47 </span>
<span>D. 48 </span>
<span>E. 49
</span>
The answer is C or 47. The object’s resultant angle of motion with the +x-axis after the collision is 47. The reason for that is f<span>rom object A’s x-momentum is 5.7 × 104 kilogram meters/second and its y-momentum is 6.2 × 104 kilogram meters/second, we know that tan of the angle from the x-axis is 6.2 / 5.7 = 1.09 and acrtan 1.09 = 47.4</span>
1st derivative = 2 cos (2x)
2nd derivative = -4sin(2x)
3rd = -8 cos(2x)
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20th derivative= 2^20 sin(2x)
