Answer:
- rate of the boat in still water = 6.5 miles / hour
- rate of the current = 2.5 miles / hour.
Explanation:
<u>1) Name the two variables:</u>
- b: rate of the boat in still water:
With that, the net rates of the boat down the river and upstrean are:
<u>2) Now set the equations for the distance as a function of the times and the rates:</u>
- downstream: 18 miles = (b + c) × 2 hours
- upstream: 18 miles = (b - c) × 4.5 hours
<u>3) Set the system of equations:</u>
- 18 = 2(b + c) ⇒ 9 = b + c . . . Equation (1)
- 18 = 4.5 (b - c) ⇒ 4 = b - c . . . Equation (2)
<u>4) Solve the system by </u><u>elimination</u><u>:</u>
- Add equations (1) and (2): 9 + 4 = 2b
- Divide both sides by 2: 13/2 = b
- Replace b with 6.5 in equation (2) and solve:
4 = 6.5 - c ⇒ c = 6.5 - 4 = 2.5
<u>5) Results:</u>
- b = rate of the boat in still water = 6.5 miles / hour
- c = rate of the current = 2.5 miles / hour.
Answer:
2.97142857143 = 104/35
Step-by-step explanation:
On calculators, anytime we're doing a fraction problem and we use calculators, It doesn't give us the fractions all it gives us is decimals, but i finally got the fraction for you. hope this helped
Make sure nobody copied and pasted my answer because i would be WILLING TO report their answer for copying and pasting
The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is

Dividing we get,

Adding, we have,

Thus, the total time taken by Joshua is 
To determine the average speed we use the formula,

where
and 
Hence, substituting the values we have,

Dividing, we get,

Thus, the average speed of Joshua during that time is 2500 m/h.
Answer:
- <u>Option A. about 100.5ft²</u>
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Explanation:
Since the <em>bases</em> must not be painted, their areas are <em>not included</em> in the calculation.
The <em>surface</em> to paint, of each pillar, is equal to the lateral area of a<em> cylinder </em>with he dimensions given.
The formula for the laeral area of a cylinder is:

Substitute including the conversion factor to convert inches to feet:
