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tatuchka [14]
1 year ago
8

An object travels around a circle of radius r with constant speed. If s is the distance traveled in time t around the circle and

theta is the central angle​ (in radians) swept out in time​ t, then the linear speed of the object is vequals​_____ and the angular speed of the object is omegaequals​______.
Mathematics
1 answer:
Alex1 year ago
4 0

Answer with Step-by-step explanation:

We are given that

Radius of circle=r

Total distance traveled =s

Time=t

Central angle=\theta rad

We know that

Linear speed,v=\frac{distance}{time}

Using the formula

Therefore, v=\frac{s}{t}

Angular speed,\omega=\frac{Angular\;displacement}{time}

By using the formula

\omega=\frac{\theta}{t} rad/s

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(i) It represents change in expenditure by candidates A; (ii) H_0:\beta_1+\beta_2=0

Step-by-step explanation:

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Under ideal conditions a certain bacteria population is known to double every three hours. Suppose that there are initially 100
lara [203]

Answer:

the estimation of the size of the population after 20 hours is 10159

Step-by-step explanation:

The computation of the size of the population after 20, hours is shown below;

= 100  2^(20 by 3)

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If we divide 20 by 3 so it would give 6.66 that lies between 6 and 7

So the estimation of the size of the population after 20 hours is 10159

hence, the same is relevant

3 0
1 year ago
Read 2 more answers
PLEASE ANSWER THIS!!!!!!!!
sergiy2304 [10]

9514 1404 393

Answer:

  (a)  x - y + 1 = 0

Step-by-step explanation:

One way to address multiple-choice questions is to try the answers to see what works.

For the lower left point (1, 2), the answer choices shown give ...

  x -y +1 = 1 -2 +1 = 0 . . . . . equation works

  -x -y +1 = -1 -2 +1 = -2 . . . doesn't work

  y -x +1 = 2 -1 +1 = 2 . . . . . doesn't work

The appropriate choice is ...

  x - y + 1 = 0

3 0
1 year ago
Find the general solution of y''' + 6y'' + y' − 34y = 0 if it is known that y1 = e−4x cos(x) is one solution.
SashulF [63]

Answer:

Step-by-step explanation:

Given is a differential equation of III order,

y''' + 6y'' + y' - 34y = 0

The characteristic equation would be cubic as

m^3+6m^2+m-34=0

By trial and error, we find that

f(2) = 2^3+6(2^2)+2-34 =0\\

Thus m=2 is one solution

Since given that e^{-4x} cos xis one solution we get

m = -4+i and hence other root is conjugate m=-4-i

Hence general solution would be

y=Ae^{2x} +e^{-4x} (Bcosx +C sinx)

3 0
2 years ago
In preparing for holiday festivities, confetti is stuffed into decorative spherical containers. Each container has a diameter of
professor190 [17]

Answer:

C. 905 in³

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, sphere

We know that the volume of a sphere is expresses as

V= 4/3πr³

Given that the diameter of the sphere is 12inches

Radius r= 12/2= 6 inches

Substituting our radius we can solve for the volume

V=4/3(3.142*6³)

V= (4*3.142*216)/3

V= 2714.68/3

V= 904.9in³

Approximately V= 905in³

5 0
1 year ago
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