Question

Under ideal conditions a certain bacteria population is known to double every three hours. Suppose that there are initially 100 bacteria. Estimate the size of the population after 20 hours.

Answer 1

Answer:

The answer is "10159"

Step-by-step explanation:

Every 3 hours the population doubles, with an initial population of 100.

$\to P(t) = 100 \times 2^{\frac{t}{3}}$

$P(t)= \text{The population of bacteria}\\\\ t = \text{time in hours}$

when t=20

$\to p(20)= 100 \times 2^{\frac{20}{3}}$

             $= 100 \times 101.593667\\\\ =10159.3667$

Answer 2

Answer:

the estimation of the size of the population after 20 hours is 10159

Step-by-step explanation:

The computation of the size of the population after 20, hours is shown below;

= 100  2^(20 by 3)

= 10159.36

If we divide 20 by 3 so it would give 6.66 that lies between 6 and 7

So the estimation of the size of the population after 20 hours is 10159

hence, the same is relevant