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Andrews [41]
2 years ago
12

Find the general solution of y''' + 6y'' + y' − 34y = 0 if it is known that y1 = e−4x cos(x) is one solution.

Mathematics
1 answer:
SashulF [63]2 years ago
3 0

Answer:

Step-by-step explanation:

Given is a differential equation of III order,

y''' + 6y'' + y' - 34y = 0

The characteristic equation would be cubic as

m^3+6m^2+m-34=0

By trial and error, we find that

f(2) = 2^3+6(2^2)+2-34 =0\\

Thus m=2 is one solution

Since given that e^{-4x} cos xis one solution we get

m = -4+i and hence other root is conjugate m=-4-i

Hence general solution would be

y=Ae^{2x} +e^{-4x} (Bcosx +C sinx)

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No

Step-by-step explanation:

Because, the Pythagorean Inequality Theorem states that the two smallest angles should add up to be more than the third angle.

4+6=10  

11 is bigger than 10, still.

Therefore, no the triangle is not possible.

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The third graders at Grace Hardeman Elementary want to play kickball. There are 20 students, and each team will have 5 students.
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D

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1 year ago
In a multiple choice exam, there are 5 questions and 4 choices for each question (a, b, c, d). Nancy has not studied for the exa
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Answer:

Part 1

a) 0.0791

b) 0.000977

c) 0.7627

Part 2

a) 0.049

b) 0.067

c) 0.864 or 0.136 (depending on what the question truly says)

d) 0.806

Step-by-step explanation:

Part 1

Since there are 4 choices per question, and only one correct answer per question.

The probability of getting a question right = (1/4) = 0.25

Probability of getting a question wrong = 1 - 0.25 = 0.75

a) Probability that the first question she gets right is the 5th question means she gets the first 4 questions wrong, and gets the last question.

0.75 × 0.75 × 0.75 × 0.75 × 0.25 = 0.0791

b) Probability that she gets all of the questions right

0.25 × 0.25 × 0.25 × 0.25 × 0.25 = 0.000977

c) Probability that she gets at least one question right = 1 - (probability that she doesn't get any question right) = 1 - (0.75⁵) = 1 - 0.2373 = 0.7627

Part 2

We use standard normal distribution for this

a) Area under (Z< -1.65) = P(z < -1.65) = 1 - P(z ≥ -1.65) = 1 - P(z ≤ 1.65) = 1 - 0.951 = 0.049

b) Area under (Z > 1.5) = P(z > 1.5) = 1 - P(z ≤ 1.5) = 1 - 0.933 = 0.067

c) P(z > -1.1) or P(z < -1.1)

P(z > - 1.1) = 1 - P(z ≤ -1.1) = 1 - 0.136 = 0.864

P(z < - 1.1) = 1 - P(z ≥ - 1.1) = 1 - P(z ≤ 1.1) = 1 - 0.864 = 0.136

d) |Z|>1.3 = P(-1.3 < z < 1.3) = P(z < 1.3) - P(z < -1.3)

P(z < 1.3) = 1 - P(z ≥ 1.3) = 1 - P(z ≤ -1.3) = 1 - 0.097 = 0.903

P(z < -1.3) = 1 - P(z ≥ -1.3) = 1 - P(z ≤ 1.3) = 1 - 0.903 = 0.097

P(z < 1.3) - P(z < -1.3) = 0.903 - 0.097 = 0.806

6 0
2 years ago
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