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Andrews [41]
2 years ago
12

Find the general solution of y''' + 6y'' + y' − 34y = 0 if it is known that y1 = e−4x cos(x) is one solution.

Mathematics
1 answer:
SashulF [63]2 years ago
3 0

Answer:

Step-by-step explanation:

Given is a differential equation of III order,

y''' + 6y'' + y' - 34y = 0

The characteristic equation would be cubic as

m^3+6m^2+m-34=0

By trial and error, we find that

f(2) = 2^3+6(2^2)+2-34 =0\\

Thus m=2 is one solution

Since given that e^{-4x} cos xis one solution we get

m = -4+i and hence other root is conjugate m=-4-i

Hence general solution would be

y=Ae^{2x} +e^{-4x} (Bcosx +C sinx)

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Answer:

  WS=8\ units

Step-by-step explanation:

we know that

If two triangles are similar

then

the ratio of their corresponding sides are equal and the corresponding angles are also equal

In this problem

\frac{TU}{TR}=\frac{UW}{RS}=\frac{TW}{TS}

we have

TU=3\ units, RS=15\ units, TW=4\ units,TR=9\ units

Find the value of TS

\frac{TU}{TR}=\frac{TW}{TS}

substitute

\frac{3}{9}=\frac{4}{TS}

TS=36/3=12\ units

WS=TS-TW

WS=12-4=8\ units

see the attached figure to better understand the problem

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1 year ago
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Find the 12th term of the geometric sequence 2, -8,32, ...
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2 years ago
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Answer:

The given transformation are;

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Step-by-step explanation:

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2. Try using changes along the x axis as changes in the independent variable, x, in the function f(x) as follows;

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3. The outline of the answers can be presented as follows

The given transformation are;

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2 years ago
Step A: = –c + = Step B: = Determine the justification for the steps from the derivation of the quadratic formula. Justification
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