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2 years ago

Find the 12th term of the geometric sequence 2, -8,32, ...

Mathematics

2 answers:

Sladkaya [172]2 years ago

8 0

Answer:

Step-by-step explanation:

hello :

the n-ieme term is : An=A1×r^(n-1)

A1 the first term r : the common ratio

in this exercice : A1 =2 r = 32/-8=-8/2 = - 4 n = 12

A12=2×(-4)^(12-1) = -2×4^11 because : ((-4)^(11)= - 4^11

Stells [14]2 years ago

7 0

Answer:

-8388607

Step-by-step explanation:

a = 2

r = -8/2 = -4

12th term = (2)×(-4)¹¹

= -8388608

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renu purchased an air conditioner for rs 40500 including 8% VAT. what was the price before including VAT?

jekas [21]

Answer:

₹ 37500

Step-by-step explanation:

Let the price before VAT be ₹x.

$\therefore \: x + 8 \% \: of \: x = 40500 \\ \therefore \: x +0.08x = 40500 \\ \therefore \: 1.08x = 40500 \\ \therefore \: x = \frac{40500}{1.08} \\ \huge \red{ \boxed{ \therefore \: x = Rs. \: 37,500}}$

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2 years ago

∆ABC has vertices at A(12, 8), B(4, 8), and C(4, 14). ∆XYZ has vertices at X(6, 6), Y(4, 12), and Z(10, 14). ∆MNO has vertices a

koban [17]

To get the length of each side,
use the distance formula with equation:
Distance = ((x2-x1)^2+(y2-y1)^2)^0.5
Solving
AB = 8 units BC = 6 units AC = 10 units
MN =8units NO = 6 units MO = 10 units
XY = 6.32 units YZ = 6.32 units XZ = 8.94 units
JK = 4.47 units KL = 4.47 units JL = 6 units

1 The right answer is the letter b) triangle ABC and Triangle MNO are Congruent triangles
ABC and MNO are triangles that have the same lengths of its three sides.

2 The answer is the letter c) rotation
There is a rotation of 90º about ABC and MNO the origin is B=N
B=N
C----------O
A----------M

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2 years ago

The probability of a train arriving on time and leaving on time is 0.8. The probability that the train arrives on time and leave

kkurt [141]

Answer:

0.9524

Step-by-step explanation:

Note enough information is given in this problem. I will do a similar problem like this. The problem is:

The Probability of a train arriving on time and leaving on time is 0.8.The probability of the same train arriving on time is 0.84. The probability of the same train leaving on time is 0.86.Given the train arrived on time, what is the probability it will leave on time?

Solution:

This is conditional probability.

Given:

Probability train arrive on time and leave on time = 0.8
Probability train arrive on time = 0.84
Probability train leave on time = 0.86

Now, according to conditional probability formula, we can write:

$P(Leave \ on \ time | arrive \ on \ time)$ = P(arrive ∩ leave) / P(arrive)

Arrive ∩ leave means probability of arriving AND leaving on time, that is given as "0.8"

and

P(arrive) means probability arriving on time given as 0.84, so:

0.8/0.84 = 0.9524

This is the answer.

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Arturiano [62]

Answer:

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Step-by-step explanation:

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8 0

2 years ago

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