Answer:
Cov(X, Y) =0.029.
Step-by-step explanation:
Given that :
The noise in a particular voltage signal has a constant mean of 0.9 V. that is μ = 0.9V ............(1)
Also, the two noise instances sampled τ seconds apart have a bivariate normal distribution with covariance.
0.04e–jτj/10 ............(2)
Having X and Y denoting the noise at times 3 s and 8 s, respectively, the difference of time = 8-3 = 5seconds.
That is, they are 5 seconds apart,
τ = 5 seconds..............(3)
Thus,
Cov(X, Y), for τ = 5seconds = 0.04e-5/10
= 0.04e-0.5 = 0.04/√e
= 0.04/1.6487
= 0.0292
Thus, Cov(X, Y) =0.029.
6(15) + 10b > = 200
90 + 10b > = 200
10b > = 200 - 90
10b > = 110
b > = 110/10
b > = 11
so she can do 15 days of running plus 11 days of biking....which totals 26 days
<u>I'm assuming you're formula is "</u><span><u>C=a/(a+12)*A" as that is only logical</u></span><span>
You get the formula </span><u>"C=a/(a+12)*A"
</u>You insert the numbers given, in place of the letters given.
<u>
</u>C=6/(6+12)*180
<u />C=3*180
C=540 mg
Which is of course wrong because it is more than the adults dosage. What i'm trying to say is "Your formula is incorrect , follow the steps I gave, but use the correct formula"