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sashaice [31]
2 years ago
12

Mr.Anderson is building a triangular- shaped roof for his shed. The triangle must be isosceles with its base (noncongruent) side

measuring 14 feet. The length of one of the congruent legs mist be greater than what value?
Mathematics
1 answer:
goldfiish [28.3K]2 years ago
4 0
The side of the congruent side of the triangle should be greater than 7 feet.
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Imaginá que tenés 125 dados cúbicos del mismo tamaño ¿Cuantos dados de altura tiene el cubo de mayor tamaño que podés armar apil
kumpel [21]

Answer:

(i) Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

Step-by-step explanation:

(i) Sabemos por la Geometría Euclídea del Espacio que un cubo es un sólido regular con 6 caras cuadradas y longitudes iguales. Cada dado tiene un volumen de 1 dado cúbico y 125 dados dan un volumen total de 125 dados cúbicos.

El volumen de un cubo está dado por la siguiente fórmula:

V = L^{3}

Donde:

L - Longitud de la arista, medida en dados.

V - Volumen del cubo, medido en dados cúbicos.

Ahora, necesitamos despejar la longitud de la arista para calcular la altura máxima posible:

L = \sqrt[3]{V}

Dado que V = 125\,dados^{3}, encontramos que la altura del cubo de mayor tamaño sería:

L =\sqrt[3]{125\,dados^{3}}

L = 5\,dados

Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) El área cuadrada formada por cubos está determinada por la siguiente fórmula:

A = L^{2}

Donde:

L - Longitud de arista, medida en dados.

A - Área, medida en dados cuadrados.

Puesto que la longitud de arista se basa en un conjunto discreto, esto es, el número de dados disponibles, debemos encontrar el valor máximo de L tal que no supere 125 y de un área entera. Es decir:

L \leq 125\,dados

Si cada cubo tiene un área de 1 dado cuadrado, entonces un cuadrado conformado por 125 dados tiene un área total de 125 dados cuadrados. Entonces:

L^{2}< 125\,dados^{2}

Esto nos lleva a decir que:

L < 11.180\,dados

Entonces, la longitud máxima del cuadrado con la mayor cantidad de cubos posible es de 11 dados. El número total requerido de cubos es el cuadrado de esa cifra, es decir:

n = (11\,dados)^{2}

n = 121\,dados

Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

4 0
2 years ago
Which graph could represent a car that begins by increasing its speed, then travels at a constant speed, and then decreases its
Savatey [412]
The graph would almost look like this

8 0
1 year ago
Read 2 more answers
An elevator weighing 15,000 newtons is raised one story in 50 seconds. If the distance between stories is 3.0 meters, how much p
Pavel [41]
Power
= Work done  /  Time
= 15000 N * 3 m / 50 s
= 45000/50  N-m/s
= 900 W

It may sound like an extremely low value, but 3.0 / 50 s is also a very slow speed.

8 0
2 years ago
Read 2 more answers
Which statement is true about the value of StartAbsoluteValue 6 EndAbsoluteValue?
Nimfa-mama [501]
(6) absolute value is 6, and if it has a -( then it means the numbers are negative.

So C. I believe.

If I’m right please give me brainiest.
I might be wrong if so please say so and why,
My notifications for Brainly is down and glitching so I won’t see and comments or questions for this.
I ask you to say it’s wrong and why for the other people that have this question and use this.

Thank you,
Have a nice day.
Hope this helps you in some way.
- Pam Pam
5 0
1 year ago
Read 2 more answers
After Paul hiked 5/6 of a mile, he was 2/3 of the way along the trail. How long is the trail?
Anvisha [2.4K]

Answer:

1.25 miles.

Step-by-step explanation:

Let x be the length of trail. We have been given that after Paul hiked \frac{5}{6} of a mile, he was \frac{5}{6} of the way along the trail.  

Let need to find x such that \frac{2}{3} of x equals \frac{5}{6}.  

\frac{2}{3} x=\frac{5}{6}

x=\frac{5}{6}\times \frac{3}{2}

x=\frac{5}{2}\times\frac{1}{2}  

x=\frac{5}{2\times 2}

x=\frac{5}{4}  

x=1\frac{1}{4}=1.25  

Therefore, the trail is 1.25 miles long.  





3 0
1 year ago
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