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2 years ago

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Mr.Anderson is building a triangular- shaped roof for his shed. The triangle must be isosceles with its base (noncongruent) side

measuring 14 feet. The length of one of the congruent legs mist be greater than what value?

1 answer:

goldfiish [28.3K]2 years ago

4 0

The side of the congruent side of the triangle should be greater than 7 feet.

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To complete her holiday wrapping, Bella needs identical strips of ribbon measuring 3.5 feet each. She has 85 feet of ribbon in t

MA_775_DIABLO [31]

Bella can cut 24 pieces of ribbon from this long strip

<u>Solution:</u>

Given that Bella has 85 feet of ribbons in total

She needs identical strips of ribbon measuring 3.5 feet each

To find: Number of peices of ribbon can she cut from long strip

Number of peices of ribbon can she cut from long strip can be calculated by dividing the total feet of ribbon she has by length of identical strips she needs

<em><u>Mathematically written as:</u></em>

$\text { Number of Strip that can be cut }=\frac{\text { Total length of ribbon }}{\text { Length of each piece }}$

$\begin{array}{l}{\text { Number of Strip that can be cut }=\frac{85}{3.5}} \\\\ {\text { Number of Strip that can be cut }=24.28 \approx 24}\end{array}$

Hence , the number of strip can be 24 each of size 3.5 feet

6 0

2 years ago

Thomas is saving money for a new mountain bike. The amount (a) Thomas needs to save is more than $50.45. Which inequality models

AfilCa [17]

C.

This is because the amount is more than what he needs to save, considering that he is probably has some money in his bank already.

3 0

2 years ago

The mean sat verbal score is 486, with a standard deviation of 95. use the empirical rule to determine what percent of the score

Pavel [41]

Find the z-scores for the two scores in the given interval.

$z=\frac{x-\mu}{\sigma}$

For the score x =391, $z=\frac{391-486}{95}=\frac{-95}{95}=-1$ .

For the score x = 486, $z=\frac{486-486}{95}=0$

Now you want the area (proportion of data) under the normal distribution from z = -1 to z = 0. The Empirical Rule says that 68% of the data falls between z = -1 to z = 1. But the curve is symmetrical around the vertical axis at z = 0, so the answer you want is HALF of 68%.

8 0

2 years ago

Question not on textbook: An insurance company has 25,000 automobile policy holders. If the yearly claim of a policy holder is a

Lynna [10]

Answer:

There is 0.00022 probability that the yearly income of the insurance claims will exceed 8.3 millions.

Step-by-step explanation:

Given data:

Sample Size = n = 25,000

Mean of yearly claim = Mu = 320

Standard Deviation of yearly claim = SD = 540

What we have to find out?

Probability of total yearly claims exceeding 8.3 million?

As the total no. of policy holders is 25,000 therefore the targeted value of claim will be calculated as follows:

Targeted value of policy claim = x = Total Yearly claim / No. of Policy holders

x = (8.3 * 1.000.000) / 25,000

x = 332

Central Limit Theorem (CLT):

From Central theorem we know that: z(x) = (x - Mu)/(SD/√n) ; Equation 1

By putting values in equation 1 we have:

z(332) = (332-320)/(540 / √25,000)

z(332) = 12 / (540/158.114)

z(332) = 3.51

By using the normal distribution tables we get:

P(x <= 332) = Phi(z) = Phi(3.51)

P(x <= 332) = 0.99978

By using the probability unity method we will get:

P(x > 332) = 1 - P(x <= 332)

P(x > 332) = 1 - 0.99978

P( x > 332) = 0.00022

Thus we get the probability of total yearly claim exceeding 8.3 million equals to 0.00022.

3 0

2 years ago

Bonita is testing prototype model rocket engines. To be considered a successful launch, the rocket must reach a height of at lea

Reika [66]

Refer to the diagram shown below.

The given constraints are
(a) y ≥ 24 ft
(b ) x ≤ 10 ft
(c) y ≥ 3x
(d) y ≤ 33 ft
The acceptable region is shown shaded.

A (0, 33) satisfies all conditions
B (4, 36) fails condition (d)
C (4.8, 30.5) satisfies all conditions
D (9, 26) fails condition (c)
E (2, 22) fails condition (a)

Answer:
The acceptable points are A and C.

8 0

2 years ago

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